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我有一个包含 IP 地址和 unix TS 的文件列表。我需要获得一个去重的文件列表，但只有该主机的最新文件（这需要基于文件名中的 unix ts，而不是文件的实际 ts）。

样本数据：

192.168.1.6_1352405854.xml  192.168.1.6_1352408700.xml  192.168.1.6_1352409088.xml   192.168.189.14_1352409088.xml
192.168.1.6_1352407188.xml  192.168.1.6_1352408715.xml  192.168.1.6_1352409520.xml   192.168.189.14_1352409520.xml
192.168.1.6_1352407248.xml  192.168.1.6_1352408796.xml  192.168.1.6_1352409601.xml   192.168.189.14_1352409601.xml
192.168.1.6_1352407311.xml  192.168.1.6_1352408830.xml  192.168.1.6_1352412001.xml   192.168.189.14_1352412001.xml
192.168.1.6_1352407329.xml  192.168.1.6_1352408907.xml  192.168.1.6_1352415602.xml   192.168.189.14_1352415602.xml
192.168.1.6_1352408608.xml  192.168.1.6_1352409018.xml  192.168.189.14_1352409018.xml

所以预期的结果将是一个文件名数组，仅列出来自每个 IP 的最新文件。

就像是：

192.168.1.6_1352415602.xml

192.168.1.14_1352415602.xml

在我的代码中，我必须遍历目录结构并提取文件名和目录。

目录将是构成左侧菜单的站点名称。

这些文件将作为超链接主机名位于这些菜单项下（但我只需要来自每个主机的最新文件信息）

// Get directory list and (natural) sort it alphabetically (ignoring case)
        $glob = "xml/vpnm/*";
        $dirs = glob($glob,GLOB_ONLYDIR);
        foreach ($dirs as $d){
            $tmp[basename($d)] = basename($d);
        }
        natcasesort($tmp);
        $dirs = array_keys($tmp);
        foreach($dirs as $dir){
            $dir = basename($dir);
            $sitename = preg_replace('/_/', ' ', $dir);
            echo "<h3><a href='#'>$sitename</a></h3>";
            echo '<div>';
                // Get list of hosts in the xml/ directory based on the file name
                $year = date("Y");
                $month = date("m");
                $basepath = "xml/vpnm/$dir/$year/$month";
// note - preg_find is an include file, not a php function
 $files = preg_find('/\.xml$/D', "xml/vpnm/$dir", PREG_FIND_RECURSIVE);
                foreach ($files as $f){
                    // echo " F= $f \n";
                    $tmp[basename($f)] = basename($f);
                }
                natcasesort($tmp);
                $files = array_keys($tmp);
                natsort($files);
// do something here to deduplicate and only include the latest files.
foreach($files as $file) {
...
4

1 回答 1

1 
$dirlist = new RecursiveIteratorIterator(new RecursiveDirectoryIterator($dir));
$results = array();
foreach($dirlist as $file){
    if($file->getExtension() !='xml') continue;
    $parts = explode('_',$file->getBasename());
    if(isset($results[$parts[0]])){
        if($file->getBasename() > $results[$parts[0]]->getBasename()){
            $results[$parts[0]] = $file;
        }
    } else {
        $results[$parts[0]] = $file;
    }
}
于 2012-11-09T00:19:41.303 回答