php - 将 ORDER 添加到 SELECT 请求

Question

我正在尝试订购我的结果，但我收到了 TString 错误。有人可以告诉我在哪里或如何添加ORDER BY date DESC, paymentamount DESC：

$sql = "SELECT * FROM `Carriers` WHERE fromzip >= '".mysql_real_escape_string($_REQUEST["from"])."'".$search_string.$search_loadtype;

这是我尝试过的，但它不允许我：

  $sql = "SELECT * FROM `Carriers` WHERE fromzip >= '".mysql_real_escape_string($_REQUEST["from"])."'".$search_string.$search_loadtype ORDER BY date DESC, paymentamount DESC;

Answer 1

试试这个..

$sql = "SELECT * FROM `Carriers` WHERE fromzip >= '".mysql_real_escape_string($_REQUEST["from"])."'".$search_string.$search_loadtype." ORDER BY date DESC, paymentamount DESC";

您需要使用 (.) 将字符串值拼凑在一起。然后你还没有用引号打开字符串......

$search_loadtype ORDER BY

变成

$search_loadtype." ORDER BY

Answer 2

我认为您错过了一些报价：

  $sql = "SELECT * FROM `Carriers` WHERE fromzip >= '".mysql_real_escape_string($_REQUEST["from"])."'".$search_string." ".$search_loadtype." ORDER BY date DESC, paymentamount DESC";

Answer 3

在我看来，您的语法错误，我真的不知道 $search_string 和 $search_loadtype 从您的代码中包含什么，但请尝试以下...

    $sql = "SELECT * FROM `Carriers` WHERE fromzip >= '".mysql_real_escape_string($_REQUEST["from"])."'".$search_string.$search_loadtype . " ORDER BY date DESC, paymentamount DESC;";