1

我有一个简单的实体（为简洁起见省略了一些不相关的字段）：

@Entity
@Table(name = "tenant")
public class Tenant {

    @Id
    private String id;

    @Version @Column
    private long version = 0;

    @Column(name = "init_in_progress")
    private Boolean initializationInProgress;

}

我想通过设置true为initializationInProgress使用这样的 JPA 更新查询对所有租户进行批量更新：

    entityManager.createQuery(
            "UPDATE Tenant t " +
            "SET t.initializationInProgress = :ip")
        .setParameter("ip", initializationInProgress)
        .executeUpdate();

这适用于EclipseLink 2.2.1. 但是，当我尝试对 version 进行相同操作时2.3.3，会出现错误：

Caused by: Exception [EclipseLink-4002] (Eclipse Persistence Services - 2.3.3.v20120629-r11760): org.eclipse.persistence.exceptions.DatabaseException
Internal Exception: org.postgresql.util.PSQLException: ERROR: more than one row returned by a subquery used as an expression
Error Code: 0
Call: UPDATE tenant SET version = (SELECT (version + ?) FROM tenant WHERE ID = tenant.ID), init_in_progress = ?
    bind => [1, true]
Query: UpdateAllQuery(referenceClass=Tenant sql="UPDATE tenant SET version = (SELECT (version + ?) FROM tenant WHERE ID = tenant.ID), init_in_progress = ?")
    at org.eclipse.persistence.exceptions.DatabaseException.sqlException(DatabaseException.java:333)
    at org.eclipse.persistence.internal.databaseaccess.DatabaseAccessor.processExceptionForCommError(DatabaseAccessor.java:1494)
    at org.eclipse.persistence.internal.databaseaccess.DatabaseAccessor.executeDirectNoSelect(DatabaseAccessor.java:838)
    at org.eclipse.persistence.internal.databaseaccess.DatabaseAccessor.executeNoSelect(DatabaseAccessor.java:906)
    at org.eclipse.persistence.internal.databaseaccess.DatabaseAccessor.basicExecuteCall(DatabaseAccessor.java:592)
    at org.eclipse.persistence.internal.databaseaccess.DatabaseAccessor.executeCall(DatabaseAccessor.java:535)
    at org.eclipse.persistence.internal.sessions.AbstractSession.basicExecuteCall(AbstractSession.java:1717)
    at org.eclipse.persistence.sessions.server.ClientSession.executeCall(ClientSession.java:253)
    at org.eclipse.persistence.internal.queries.DatasourceCallQueryMechanism.executeCall(DatasourceCallQueryMechanism.java:207)
    at org.eclipse.persistence.internal.queries.DatasourceCallQueryMechanism.executeCall(DatasourceCallQueryMechanism.java:193)
    at org.eclipse.persistence.internal.queries.DatasourceCallQueryMechanism.executeNoSelectCall(DatasourceCallQueryMechanism.java:236)
    at org.eclipse.persistence.internal.queries.DatasourceCallQueryMechanism.updateAll(DatasourceCallQueryMechanism.java:789)
    at org.eclipse.persistence.queries.UpdateAllQuery.executeDatabaseQuery(UpdateAllQuery.java:153)
    at org.eclipse.persistence.queries.DatabaseQuery.execute(DatabaseQuery.java:844)
    at org.eclipse.persistence.queries.DatabaseQuery.executeInUnitOfWork(DatabaseQuery.java:743)
    at org.eclipse.persistence.queries.ModifyAllQuery.executeInUnitOfWork(ModifyAllQuery.java:145)
    at org.eclipse.persistence.internal.sessions.UnitOfWorkImpl.internalExecuteQuery(UnitOfWorkImpl.java:2871)
    at org.eclipse.persistence.internal.sessions.AbstractSession.executeQuery(AbstractSession.java:1516)
    at org.eclipse.persistence.internal.sessions.AbstractSession.executeQuery(AbstractSession.java:1498)
    at org.eclipse.persistence.internal.sessions.AbstractSession.executeQuery(AbstractSession.java:1463)
    at org.eclipse.persistence.internal.jpa.EJBQueryImpl.executeUpdate(EJBQueryImpl.java:540)
    at com.example.dao.impl.tenant.TenantRepositoryImpl.updateAllTenantsInitializationStatus(TenantRepositoryImpl.java:100)

有人熟悉这个错误吗？任何已知的解决方法/修复（除了不更改EclipseLink版本）？感谢你的帮助。

顺便说一句，我正在使用PostgreSQL 9.1.

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1 回答 1

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这最初看起来像一个数据问题，其中您有多个具有相同 ID 的行tenant......但它实际上是 EclipseLink 查询的问题。由于这是一个生成的查询，您手上似乎有一个（严重的）EclipseLink 错误。

更新：请参阅此 EclipseLink bugzilla 条目以了解错误 393223。

查询应该真正将内部引用别名为tenant，例如：

UPDATE tenant SET version = (SELECT (t2.version + ?) FROM tenant t2 WHERE t2.ID = tenant.ID), init_in_progress = ?

未能添加此别名意味着ID = tenant.ID...tenant.ID = tenant.ID这始终是正确的，因此子查询匹配tenant.

观察这个演示：

CREATE TABLE tenant ( ID integer primary key, version integer );
INSERT INTO tenant ( id, version ) values (1,0), (2,0), (3,0);

BEGIN;

PREPARE testq(integer) AS 
UPDATE tenant SET version = (SELECT (version + $1) FROM tenant WHERE ID = tenant.ID);

regress=> EXECUTE testq(1);
ERROR:  more than one row returned by a subquery used as an expression

ROLLBACK;

更正查询：

BEGIN;

PREPARE testq2(integer) AS 
UPDATE tenant SET version = (SELECT (version + $1) FROM tenant t2 WHERE t2.ID = tenant.ID);

regress=> EXECUTE testq2(1);
UPDATE 3

ROLLBACK;

这似乎是一个 EclipseLink 错误。除了将批量更新作为本机 SQL 之外，我没有看到您可以在代码中做很多事情。

于 2012-11-09T01:42:35.737 回答