php - php字符串替换让我感到困惑

Question

这是行不通的，发生了什么应该很简单:-(

    $test = "hello naughty";


$swearWords = array("naughty","notallowed");

foreach ($swearWords as $naughty)
{
    $post = str_ireplace($naughty, "<b><i>(oops)</i></b>", $test);

}

echo $post;

谢谢

Answer 1

您（总是）使用 $test 作为输入参数。
在示例notallowed中，foreach 循环的第二次迭代中的指针未找到，因此输入字符串原样$test='hello naughty'返回。

<?php
$test = "hello naughty";
$swearWords = array("naughty","notallowed");

$post = $test;
foreach ($swearWords as $naughty)
{
    $post = str_ireplace($naughty, "<b><i>(oops)</i></b>", $post);
}

echo $post;

印刷hello <b><i>(oops)</i></b>

str_ireplace 可以将针数组作为第一个参数

<?php
$test = "hello notallowed, this is naughty";
$post = str_ireplace(array("naughty","notallowed"), "<b><i>(oops)</i></b>", $test);
echo $post;

打印hello <b><i>(oops)</i></b>, this is <b><i>(oops)</i></b>。

Answer 2

您可以直接使用数组进行替换

<?php

    $test = "hello naughty";
    $swearWords = array("naughty","notallowed");
    $post = str_ireplace($swearWords, "<b><i>(oops)</i></b>", $test);
    echo $post;
?>

Answer 3

采用

$test = "hello naughty";
$swearWords = array("naughty","notallowed");
$post = str_ireplace($swearWords,"<b><i>(oops)</i></b>",$test)
echo $post;

反而。有关函数处理数组参数的方式的信息，请参见str_ireplace 。

Answer 4

试试这个

$test = "hello naughty";


$swearWords = array("naughty","notallowed");

foreach ($swearWords as $naughty)
{
//$post = str_ireplace($naughty, "(oops)", $test);
echo str_ireplace($naughty,"<b><i>(oops)</i></b>",$test)."<br>";

}

尝试编辑的代码

Answer 5

为了支持其他答案，我有几个链接显示了可以帮助您的示例。

愿这些对您有所帮助并解决您的问题。

http://www.w3schools.com/php/func_string_str_ireplace.asp

http://php.net/manual/en/function.str-ireplace.php

谢谢。

Answer 6

$swearWords = array("naughty"); 然后它说（哎呀）而不是顽皮。