1

到目前为止，这是我的代码（好吧，while循环）：

public class Lab10d
{
public static void main(String args[])
{
    Scanner keyboard = new Scanner(System.in);
    char response = 0;


    //add in a do while loop after you get the basics up and running

        String player = "";

        out.print("Rock-Paper-Scissors - pick your weapon [R,P,S] :: ");

        //read in the player value
        player = keyboard.next();

        RockPaperScissors game = new RockPaperScissors(player);
        game.setPlayers(player);
        out.println(game);
    while(response == ('y'))
    {
        out.print("Rock-Paper-Scissors - pick your weapon [R,P,S] :: ");
        player = keyboard.next();
        game.setPlayers(player);
        //game.determineWinner();
        out.println(game);
        out.println();

        //



    }
    out.println("would you like to play again? (y/n):: ");
        String resp =  keyboard.next();
        response = resp.charAt(0);
}
}

它应该额外运行代码，直到输入 n

当我输入ay时，它应该重新运行代码但没有

4

1 回答 1

4

while在您询问他们是否要再次播放之前，您的循环结束。

将循环更改为：

while(response == ('y'))
    {
        out.print("Rock-Paper-Scissors - pick your weapon [R,P,S] :: ");
        player = keyboard.next();
        game.setPlayers(player);
        //game.determineWinner();
        out.println(game);
        out.println();
        out.println("would you like to play again? (y/n):: ");
        String resp =  keyboard.next();
        response = resp.charAt(0);
    }

还有一个问题：response在循环开始之前没有设置为'y'。它根本不会在循环中做任何事情。请改用do { ... } while (response == 'y')循环。

    do
    {
        out.print("Rock-Paper-Scissors - pick your weapon [R,P,S] :: ");
        player = keyboard.next();
        game.setPlayers(player);
        //game.determineWinner();
        out.println(game);
        out.println();
        out.println("would you like to play again? (y/n):: ");
        String resp =  keyboard.next();
        response = resp.charAt(0);
    } while (response == 'y');

do-while 将执行代码一次，然后检查条件并继续执行true。while 循环只会检查条件，并继续执行 while it's true。

编辑：我为你整理了一些代码：

import java.util.Scanner;

public class Troubleshoot {

    public static void main(String[] args) {
        Scanner s = new Scanner(System.in);
        char response = ' ';
        do {
            System.out.println("Stuff");
            System.out.print("Again? (y/n): ");
            response = s.next().charAt(0);
        } while (response == 'y');
    }

}

输出：

Stuff
Again? (y/n): y
Stuff
Again? (y/n): y
Stuff
Again? (y/n): n
于 2012-11-08T01:53:25.747 回答