1

我有这个表格：

1.- 参与者

CREATE TABLE participante ( 
    id_participa    SMALLINT NOT NULL,
    nasi            INTEGER NOT NULL,
    PRIMARY KEY(id_participa,nasi),
    FOREIGN KEY(nasi) REFERENCES persona(nasi)
)

2.- 角色

CREATE TABLE persona ( 
    nasi        INTEGER NOT NULL,
    PRIMARY KEY(nasi)
)

3.- CITA 

CREATE TABLE cita ( 
    id_participa    SMALLINT NOT NULL,
    nasi            INTEGER NOT NULL,
    idcita          INTEGER NOT NULL,
    PRIMARY KEY(id_participa,idcita,nasi),
    FOREIGN KEY(id_participa, nasi) REFERENCES participante(id_participa, nasi)
)

4.- 公式

CREATE TABLE formulario ( 
        id_participa        SMALLINT NOT NULL,
        nasi                INTEGER NOT NULL,
        idcita              INTEGER NOT NULL,
        PRIMARY KEY(id_participa,idcita,nasi),
        FOREIGN KEY(id_participa, nasi, idcita) REFERENCES cita(id_participa, nasi, idcita)
    )

（在其他领域中，我只是向您展示与问题有关的领域）

这里是实体：

1.- 参与者

@Entity
@Table(name = "participante")
public class Participante implements Serializable {

    private static final long serialVersionUID = 1L;
    @Id
    @Column(name = "id_participa")
    private Integer idParticipante;
    @Id
    @OneToOne
    @JoinColumn(name = "nasi")
    private Persona persona;

2.- 角色

@Entity
@Table(name = "persona")
public class Persona implements Serializable {

    private static final long serialVersionUID = 1L;
    @Id
    @Column(name = "nasi")
    private Integer nasi;

3.- CITA

@Entity
@Table(name = "cita")
public class Cita implements Serializable {

    private static final long serialVersionUID = 1L;
    @Id
    @Column(name = "idcita")
    private Integer idCita;
    @Id
    @ManyToOne
    @JoinColumns({
            @JoinColumn(name = "id_participa", referencedColumnName = "id_participa"),
            @JoinColumn(name = "nasi", referencedColumnName = "nasi") })
    private Participante participante;

4.- 公式

@Entity
@Table(name = "formulario")
public class Formulario implements Serializable {

    private static final long serialVersionUID = 1L;
    @Id
    @OneToOne
    @JoinColumns({
            @JoinColumn(name = "id_participa", referencedColumnName = "id_participa"),
            @JoinColumn(name = "nasi", referencedColumnName = "nasi"),
            @JoinColumn(name = "idcita", referencedColumnName = "idcita") })
    private Cita cita;

当我尝试启动服务器时，我得到了这个异常：

Caused by: org.hibernate.MappingException: Unable to find column with logical name: nasi in participante
    at org.hibernate.cfg.Ejb3JoinColumn.checkReferencedColumnsType(Ejb3JoinColumn.java:575)
    at org.hibernate.cfg.BinderHelper.createSyntheticPropertyReference(BinderHelper.java:126)
    at org.hibernate.cfg.ToOneFkSecondPass.doSecondPass(ToOneFkSecondPass.java:116)
    at org.hibernate.cfg.Configuration.processEndOfQueue(Configuration.java:1514)
    at org.hibernate.cfg.Configuration.processFkSecondPassInOrder(Configuration.java:1437)
    at org.hibernate.cfg.Configuration.secondPassCompile(Configuration.java:1355)
    at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1724)
    at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1775)
    at org.springframework.orm.hibernate4.LocalSessionFactoryBuilder.buildSessionFactory(LocalSessionFactoryBuilder.java:242)
    at org.springframework.orm.hibernate4.LocalSessionFactoryBean.buildSessionFactory(LocalSessionFactoryBean.java:372)
    at org.springframework.orm.hibernate4.LocalSessionFactoryBean.afterPropertiesSet(LocalSessionFactoryBean.java:357)
    at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.invokeInitMethods(AbstractAutowireCapableBeanFactory.java:1514)
    at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1452)
    ... 73 more

编辑：我刚刚发现，如果我从注释中删除“referencedColumn”属性，我会得到一个不同的异常：

Caused by: org.hibernate.AnnotationException: A Foreign key refering es.myapp.modelo.datos.dominio.participante.Participante from es.myapp.modelo.datos.dominio.cita.Cita has the wrong number of column. should be 1
    at org.hibernate.cfg.annotations.TableBinder.bindFk(TableBinder.java:432)
    at org.hibernate.cfg.ToOneFkSecondPass.doSecondPass(ToOneFkSecondPass.java:117)
    at org.hibernate.cfg.Configuration.processEndOfQueue(Configuration.java:1514)
    at org.hibernate.cfg.Configuration.processFkSecondPassInOrder(Configuration.java:1437)
    at org.hibernate.cfg.Configuration.secondPassCompile(Configuration.java:1355)
    at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1724)
    at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1775)
    at org.springframework.orm.hibernate4.LocalSessionFactoryBuilder.buildSessionFactory(LocalSessionFactoryBuilder.java:242)
    at org.springframework.orm.hibernate4.LocalSessionFactoryBean.buildSessionFactory(LocalSessionFactoryBean.java:372)
    at org.springframework.orm.hibernate4.LocalSessionFactoryBean.afterPropertiesSet(LocalSessionFactoryBean.java:357)
    at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.invokeInitMethods(AbstractAutowireCapableBeanFactory.java:1514)
    at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1452)
    ... 73 more
4

1 回答 1

1

如果我创建辅助 PK 类，它可以工作......

例如：

@Embeddable
public class CitaPK implements Serializable{

    private static final long serialVersionUID = 1L;
    @ManyToOne
    @JoinColumns({
            @JoinColumn(name = "id_participa", referencedColumnName = "id_participa"),
            @JoinColumn(name = "nasi", referencedColumnName = "nasi") })
    private Participante participante;
    @Column(name = "idcita", columnDefinition="smallint")
    private Integer idCita;

然后在 Cita 课上：

@Entity
@Table(name = "sicco_citas")
public class Cita implements Serializable {

    private static final long serialVersionUID = 1L;
    @Id
    private CitaPK citaPK;

http://docs.jboss.org/hibernate/stable/annotations/reference/en/html/entity.html#d0e2177

于 2012-11-08T16:37:59.473 回答