python - 意外缩进 - Python def

Question

你能帮我解决这个问题吗？

def group_iter (iterator, n=2, strict=False):

    accumulator = []
        accumulator.append(item)
        if len(accumulator) == n: 
        yield tuple(accumulator)
        accumulator = []

    if strict and len(accumulator) !=0:
        raise ValuseError("Leftover values")


print "This is count %r " % group_iter 

当我运行它时，我得到：

accumulator.append (item)
IndentationError: unexpected indent

我怎么解决这个问题？谢谢！

Answer 1

您的代码缩进太远，请删除多余的空格以匹配accumulator = [].

def group_iter (iterator, n=2, strict=False):
    accumulator = []
    accumulator.append(item)
    if len(accumulator) == n: 
        yield tuple(accumulator)
        accumulator = []

您可能需要查看您的 Python 教程，了解何时缩进 Python 代码以及何时不缩进。

Answer 2

错误是否也显示行号？它应该给你一个从哪里开始的提示。（顺便说一句，它在第 4-7 行）

accumulator.append(item) # remove indent
if len(accumulator) == n: # remove indent
    yield tuple(accumulator) # keep indent
accumulator = [] # uncertain whether to keep or remove this base on your needs.