我必须将时间戳值插入表中。我通过编写存储过程来插入值。
这是我的存储过程的代码。
CREATE OR REPLACE FUNCTION dataInsert_Schedule() RETURNS boolean As
$$
DECLARE
i integer;
j integer;
dur integer;
tup Channel%rowtype;
BEGIN
FOR tup IN SELECT * FROM Channel
LOOP
for i in 0..6 LOOP --days
for j in 0..23 LOOP --hours
dur = round((random() * 2) + 1);
IF i + dur > 24 then
dur = 24 - i;
END IF;
INSERT INTO Schedule VALUES(tup.Channel_ID, round((random() * 999) + 1),( current_date + (integer to_char(i,'9')) )+ (interval to_char(j,'99') || ' hour'), (interval dur ||' hour'));
i = i + dur - 1;
END LOOP;
END LOOP;
END LOOP;
return true;
END
$$ LANGUAGE plpgsql;
当我编写查询时Select * From dataInsert_Schedule();
,出现以下错误:
ERROR: syntax error at or near "to_char"
LINE 1: ...d((random() * 999) + 1),( current_date + (integer to_char( $...
^
QUERY: INSERT INTO Schedule VALUES( $1 , round((random() * 999) + 1),( current_date + (integer to_char( $2 ,'9')) )+ (interval to_char( $3 ,'99') || ' hour'), (interval $4 ||' hour'))
CONTEXT: SQL statement in PL/PgSQL function "datainsert_schedule" near line 15
********** Error **********
ERROR: syntax error at or near "to_char"
SQL state: 42601
Context: SQL statement in PL/PgSQL function "datainsert_schedule" near line 15
我第一次尝试这个
INSERT INTO Schedule VALUES(tup.Channel_ID, round((random() * 999) + 1),( current_date + (integer ''||i) )+ (interval (j ||' hour')), (interval dur ||' hour'));
插入方式,但我遇到了同样的错误。
为什么我收到此错误?
该schedule
表定义如下:
CREATE TABLE Schedule(
Channel_ID Integer REFERENCES Channel(Channel_ID),
Program_ID Integer REFERENCES Program(Program_ID),
Start_Time Timestamp NOT NULL,
Duration Interval NOT NULL,
CONSTRAINT Schedule_Key PRIMARY KEY(Channel_ID, Program_ID)
);