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我正在使用以下代码获取地址簿中所有联系人的手机号码（即第一个电话号码）。我想将所有这些数字存储到NSArray

self.dataSource = [[NSMutableArray alloc]init]; // dataSouce is delared in .h file
ABAddressBookRef addressBook = ABAddressBookCreate();
NSMutableArray *allPeople = (__bridge NSMutableArray *)ABAddressBookCopyArrayOfAllPeople(addressBook);
int nPeople = ABAddressBookGetPersonCount(addressBook);

for(int i=0; i < nPeople; i++ ){
    ABRecordRef person = (__bridge ABRecordRef)([allPeople objectAtIndex:i]);
    NSString *name = @"";

    if(ABRecordCopyValue(person, kABPersonFirstNameProperty) != NULL)
        name = [[NSString stringWithFormat:@"%@", ABRecordCopyValue(person, kABPersonFirstNameProperty)] stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceCharacterSet]];
    [_dataSource addObject: name];

    ABMultiValueRef phoneNumberProperty = ABRecordCopyValue(person, kABPersonPhoneProperty);
    _phoneNumbers = (__bridge NSArray*)ABMultiValueCopyValueAtIndex(phoneNumberProperty, 0);
    CFRelease(phoneNumberProperty);
    NSLog(@"Phone numbers = %@", _phoneNumbers);
}

但是当我使用NSLog(@"Phone numbers = %@", _phoneNumbers);输出时

2012-11-07 15:31:06.116 contacts[4938:12b03] Phone numbers = 1 (800) 111-1111
2012-11-07 15:31:06.117 contacts[4938:12b03] Phone numbers = (222) 355-5668
2012-11-07 15:31:06.118 contacts[4938:12b03] Phone numbers = (910) 192-0192

我想要NSArray像这样的输出

Phone numbers = ( 
"1 (800) 111-1111",
"(222) 355-5668",
"(910) 192-0192" 
)

我怎样才能做到这一点 ？

4

2 回答 2

2

你可以像这样简单地做到这一点

 self.dataSource = [[NSMutableArray alloc]init]; // dataSouce is delared in .h file
    ABAddressBookRef addressBook = ABAddressBookCreate();
    NSMutableArray *allPeople = (__bridge NSMutableArray *)ABAddressBookCopyArrayOfAllPeople(addressBook);
    int nPeople = ABAddressBookGetPersonCount(addressBook);

    NSMutableArray *arrContacts = [[NSMutableArray alloc] init];

    for(int i=0; i < nPeople; i++ ){
        ABRecordRef person = (__bridge ABRecordRef)([allPeople objectAtIndex:i]);
        NSString *name = @"";

        if(ABRecordCopyValue(person, kABPersonFirstNameProperty) != NULL)
            name = [[NSString stringWithFormat:@"%@", ABRecordCopyValue(person, kABPersonFirstNameProperty)] stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceCharacterSet]];
        [_dataSource addObject: name];

        ABMultiValueRef phoneNumberProperty = ABRecordCopyValue(person, kABPersonPhoneProperty);
        _phoneNumbers = (__bridge NSArray*)ABMultiValueCopyValueAtIndex(phoneNumberProperty, 0);
        CFRelease(phoneNumberProperty);
        NSLog(@"Phone numbers = %@", _phoneNumbers);
        [arrContacts addObject:_phoneNumbers];
    }
    NSLog(@"Phone numbers : %@",arrContacts);
于 2012-11-07T11:00:52.167 回答
1

我通过 Google 找到了这个，并以这个地址簿代码为例，但发现了一个错误，我会为其他来到这里的人更正。

使用ABMultiValueCopyValueAtIndex时返回一个类型CFTypeRef。该函数仅获取该索引处的电话号码（在本例中为索引 0），在电话号码的情况下CFStringRef，不应将其转换为NSArray*.

ABMultiValueCopyArrayOfAllValues将是获取存储在联系人中的所有电话号码数组的正确调用。这可以存储到一个数组中并像萨拉法拉兹在他的回答中所做的那样记录下来。

NSArray *_phoneNumbers = (__bridge NSArray*)ABMultiValueCopyArrayOfAllValues(phoneNumberProperty);

如果您只想获得第一个电话号码，您可以这样做：

CFStringRef phoneNumberRef = ABMultiValueCopyValueAtIndex(phoneNumberProperty, 0);
NSString *phoneString = (__bridge NSString*)phoneNumberRef;
于 2013-02-11T21:33:40.197 回答