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嗯使用此代码将接收到的图像存储在硬盘内存中
我尝试编辑此代码以将接收到的图像文件存储在动态图像对象中,而不存储在硬盘内存中

    private void StartReceiving()
    {
        try
        {
              string hstServer = Dns.GetHostName();
             IPAddress ipaLocal ="127.0.0.1";


            if (tlsServer == null)
            {
                tlsServer = new TcpListener(ipaLocal, Convert.ToInt32(txtPort.Text));
            } 
            tlsServer.Start(); 
            TcpClient tclServer = tlsServer.AcceptTcpClient(); 
            strRemote = tclServer.GetStream(); 
            int bytesSize = 0;
            byte[] downBuffer = new byte[2048];
            bytesSize = strRemote.Read(downBuffer, 0, 2048);
           FileName = System.Text.Encoding.ASCII.GetString(downBuffer, 0, bytesSize);
           try
           {
               strLocal = new FileStream(FileName, FileMode.Create, FileAccess.Write, FileShare.ReadWrite);
           }catch(Exception exp)
           {
               strLocal = new FileStream(FileName.Substring(0,5), FileMode.Create, FileAccess.Write, FileShare.ReadWrite);
           }
            downBuffer = new byte[2048];

            bytesSize = strRemote.Read(downBuffer, 0, 2048);

            downBuffer = new byte[2048];

            while ((bytesSize = strRemote.Read(downBuffer, 0, downBuffer.Length)) > 0)
            {
                strLocal.Write(downBuffer, 0, bytesSize);
            }

        }
        finally
        {
            strLocal.Close();
            strRemote.Close();

        }
    }

在 .net 4 中使用 CopyTo 进行编辑

            tlsServer.Start(); 
            TcpClient tclServer = tlsServer.AcceptTcpClient();
           tclServer.GetStream().CopyTo(ms);

            //Get the image out of the stream
            Image img = Image.FromStream(ms);


        }
        finally
        {
            m = Image.FromStream(strLocal);
            strLocal.Close();
            strRemote.Close();

        }
4

1 回答 1

2

根据此处的详细信息:

MemoryStream ms = new MemoryStream();
//This call will block until the client disconnects though
tclServer.GetStream().CopyTo(ms);

//Get the image out of the stream
Image img = Image.FromStream(ms);
于 2012-11-06T23:35:58.343 回答