我需要有人向我展示如何创建一个简单的表来搜索我从该表单中插入的每一列数据。我正在寻找最简单的方法来创建一个带有可以过滤每一列的搜索框的表。DB:Mysql 字段类型:文本 下面显示了我用于将数据发布到数据库的表单的变量。
<?php
if (isset($_POST["submit"]) && $_POST["submit"] == "Submit")
{
for ($count = 1; $count <= 9; $count++)
{
$fields[$count] = "";
if (isset($_POST["field" . $count . ""]))
{
$fields[$count] = trim($_POST["field" . $count . ""]);
//echo $fields[$count] . "<br />";
}
}
$con = mysql_connect("local", "user", "pass");
mysql_select_db("DB", $con);
$fromzip = mysql_real_escape_string($_POST['fromzip']);
$tozip = mysql_real_escape_string($_POST['tozip']);
$insert = "INSERT INTO Carriers (`fromzip` ,`tozip` ,`date`) VALUES('$fromzip' ,'$tozip' , NOW())";
mysql_query($insert) or die(mysql_error());
$select = "SELECT `fromzip` ,`tozip` , FROM `Carriers` ORDER BY `date` DESC;";
$result = mysql_query($select) or die(mysql_error());
}
?>
<style ="text-align: center; margin-left: auto; margin-right: auto;"></style>
</head>
<body>
<div
style="border: 2px solid rgb(0, 0, 0); margin: 16px 20px 20px; width: 400px; background-color: rgb(236, 233, 216); text-align: center; float: left;">
<form action="" method="post";">
<div
style="margin: 8px auto auto; width: 300px; font-family: arial; text-align: left;"><br>
<table style="font-weight: normal; width: 100%; font-size: 12px;"
border="1" bordercolor="#929087" cellpadding="6" cellspacing="0">
<table
style="font-weight: normal; width: 100%; text-align: right; font-size: 12px;"
border="1" bordercolor="#929087" cellpadding="6" cellspacing="0">
<tbody>
<tr>
<td style="width: 35%;">Pick Zip:</td><td> <input id="fromzip" name="fromzip" maxlength="50"
style="width: 100%;" type="text">
</tr>
<tr>
<td style="width: 35%;">Drop Zip:</td><td> <input id="tozip" name="tozip" maxlength="50"
style="width: 100%;" type="text">
</tr>
</tbody>
</table>
<p style="text-align: center;"><input name="submit" value="Submit"
class="submit" type="submit"></p>
</div>
</form>
</div>
<p style="margin-bottom: -20px;"> </p>
</body>