我正在尝试使用Haversine 公式从 WordPress 数据库中获取最近的位置
我的表结构如下
帖子
+--------------+
| Field |
+--------------+
| ID |
| post_author |
| post_title |
| post_type |
+--------------+
后元
+--------------+
| Field |
+--------------+
| meta_id |
| post_id |
| meta_key |
| meta_value |
+--------------+
并有记录meta_key
值latitude
和longitude
有关我用来获取纬度和经度的 SQL,请参阅我上一个问题的答案。
SELECT p.ID,
p.post_title,
p.post_author,
max(case when pm.meta_key='latitude' then pm.meta_value end) latitude,
max(case when pm.meta_key='longitude' then pm.meta_value end) longitude
FROM `wp_posts` p
LEFT JOIN `wp_postmeta` pm
on p.ID=pm.post_id
WHERE p.post_type='place'
AND (pm.meta_key='latitude' OR pm.meta_key='longitude')
GROUP BY p.ID, p.post_title, p.post_author
ORDER BY p.ID ASC
现在我想将上面的查询合并到这个问题的答案中
SELECT item1, item2,
( 3959 * acos( cos( radians(37) )
* cos( radians( lat ) )
* cos( radians( lng )
- radians(-122) )
+ sin( radians(37) )
* sin( radians( lat ) )
)
) AS distance
FROM geocodeTable
HAVING distance < 25
ORDER BY distance LIMIT 0 , 20;
以下是通过组合查询
SELECT ID,
post_title,
post_author,
max(case when meta_key='latitude' then meta_value end) latitude,
max(case when meta_key='longitude' then meta_value end) longitude,
( 3959 * acos( cos( radians(18.204540500000) )
* cos( radians( latitude ) )
* cos( radians( longitude )
- radians(-66.450958500000) )
+ sin( radians(18.204540500000 )
* sin( radians( latitude ) )
)
) AS distance
FROM `wp_posts`
LEFT JOIN `wp_postmeta`
on ID=post_id
WHERE post_type='place'
AND (meta_key='latitude' OR meta_key='longitude')
GROUP BY ID, post_title, post_author
ORDER BY ID ASC
但这会产生语法错误
#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'AS distance FROM `wp_posts` LEFT JOIN `wp_postmeta` on ID=post_id WHERE po' at line 13