sql - SQL Server 2000 从最大日期查询总值和值

Question

我有这个有价值的 RoomTable

SID   Room   Date        APhase   BPhase   ACount  BCount
1     One    10/28/2012  4        5         3       6
2     One    10/29/2012  2        3        -1      -1
3     One    10/30/2012  4        5         7      -1
4     Two    10/28/2012  8        3         2       3
5     Two    10/30/2012  3        5         4       6
6     Three  10/29/2012  5        8         2      -1
7     Three  10/30/2012  5        6        -1       4
8     Four   10/29/2012  6        2        -1      -1
9     Four   10/30/2012  5        8        -1      -1

我想要的是返回以下内容：

1. 每个房间的 APhase 和 BPhase 的总和。
2. 从每个房间的最大日期开始的 ACount 和 BCount 的值
3. 如果 ACount 值为 -1，则使用前一个日期。与 BCount 相同。
4. 如果 ACount 值为 -1 且前一个日期为 -1，依此类推。然后使用 0。与 BCount 相同。

我可以用这个查询得到 1 号的查询

SELECT Room, sum(APhase) as TotalAPhase, sum(BPhase) as TotalBPhase 
FROM RoomTable 
WHERE Date between '10/28/2012' and '10/30/2012'
group by Room
order by Room

但我对如何包含数字 2-4 查询感到困惑。

这是我想要的输出

Room  TotalAPhase  TotalBPhase  ACount   BCount
One   10           13           7        6
Two   11           8            4        6
Three 10           13           2        4
Four  11           10           0        0

任何想法将不胜感激。谢谢。

Answer 1

希望这适用于您的情况：

SELECT 
Room
,SUM(APhase) AS TotalAPhase
,SUM(BPhase) AS TotalBPhase 
,ISNULL((    SELECT TOP 1 RT1.ACount 
             FROM RoomTable RT1 
             WHERE RT1.Room = RT.Room 
                AND RT1.ACount != -1
             ORDER BY RT1.Date DESC
), 0) AS ACount
,ISNULL((   SELECT TOP 1 RT2.BCount 
            FROM RoomTable RT2
            WHERE RT2.Room = RT.Room 
               AND RT2.BCount != -1
            ORDER BY RT2.Date DESC
), 0) AS BCount

FROM RoomTable RT
--WHERE Date between '10/28/2012' and '10/30/2012'
GROUP BY Room
ORDER BY Room

我不确定你是否真的需要那个 where 子句，所以我把它注释掉了。从这个 SQL Fiddle 演示中可以看出，结果表上 Room 3 的 TotalBPhase 值应该是 14 。

Answer 2

您可以使用@yildizm85 的答案，或者如果您想要更高性能的代码，您可以将所有任务分解为更小的步骤并使用表变量来实现相同的目标。请参阅下面的查询...

declare @roomResult table
(Room nvarchar(50), maxadate datetime, maxbdate datetime, TotalAPhase int , TotalBPhase int , acount int, bcount int)

insert into @roomResult 
SELECT Room, null,null,sum(APhase) as TotalAPhase, sum(BPhase) as TotalBPhase ,0,0
FROM RoomTable 
group by Room
order by Room

update @roomresult 
set maxadate = mxdate  
from 
(
select room roomname, max( date) mxdate  from
(
select room, date , case when acount = -1 then null else acount end acount , case when bcount = -1 then null else bcount end bcount 
from roomtable ) as a where a.acount is not null
 group by room
) b inner join @roomresult c on b.roomname = c.room


update @roomresult 
set maxbdate = mxdate  
from 
(
select room roomname, max( date) mxdate  from
(
select room, date , case when bcount = -1 then null else bcount end bcount 
from roomtable ) as a where a.bcount is not null
 group by room
) b inner join @roomresult c on b.roomname = c.room

update @roomresult 
set acount = r.acount
from @roomresult rr inner join roomtable r
on rr.room = r.room and rr.maxadate = r.date

update @roomresult 
set bcount = r.bcount
from @roomresult rr inner join roomtable r
on rr.room = r.room and rr.maxbdate = r.date

select Room,TotalAPhase,TotalbPhase,ACount,BCount From @roomResult 

Answer 3

您可以尝试查询类似这样的内容>>>

SELECT Room, sum(APhase) as TotalAPhase, sum(BPhase) as TotalBPhase 
FROM RoomTable 
WHERE Date =(select max(Date) from RoomTable group by Room order by Room)
and ACount=(update RoomTable set ACount=0 where ACount<0) and and ACount=(update RoomTable set BCount=0 where BCount<0)
group by Room 
order by Room