好吧,第一次问问题通常我可以通过快速搜索找到这些类型的答案,这让我太沮丧了。这是一个简单的小程序,需要工作时间和工资率才能获得总工资和净工资,其中大部分只是我的试运行(净工资等的金额),但在我走得更远之前,我想让它工作。
按下按钮时没有任何反应,不完全确定原因。(最近,当我尝试这个和那个时,我开始在 IE 中得到一个 NullPointerException,可能与我的问题无关,但也只是把它扔在那里。)感谢任何帮助,我尝试了一些事情,但我肯定java生锈了!
继承人的代码:
import javax.swing.*;
import java.awt.*;
import java.awt.event.*;
public class ButtonGrossPay extends JApplet implements ActionListener
{
private JTextField txtHourWork;
private JTextField txtHourRate;
private JLabel lblGrossPay;
private JLabel lblNetPay;
public void init () {
Container content_pane = getContentPane ();
content_pane.setLayout (new FlowLayout ());
JLabel lblHourWork = new JLabel("Hours Worked");
JTextField txtHourWork = new JTextField(10);
JLabel lblHourRate = new JLabel("Pay Rate");
JTextField txtHourRate = new JTextField(10);
JButton btnCalculate = new JButton("Calculate Pay");
btnCalculate.addActionListener(this);
content_pane.add (lblHourWork);
content_pane.add(txtHourWork);
content_pane.add(lblHourRate);
content_pane.add(txtHourRate);
content_pane.add(btnCalculate);
content_pane.add(lblGrossPay);
content_pane.add(lblNetPay);
}
public void actionPerformed (ActionEvent event) {
String firstNumber = txtHourWork.getText();
String secondNumber = txtHourRate.getText();
int number1 = Integer.parseInt(firstNumber);
int number2 = Integer.parseInt(secondNumber);
int gross = number1 * number2;
double netPay = 0;
if (gross >= 0 && gross <= 99.99) {
netPay = gross - gross * .10;
} else if (gross >= 99.99) {
netPay = gross - gross * .20;
}
lblGrossPay.setText(Integer.toString(gross));
lblNetPay.setText(Double.toString(netPay));
}
}