我有一个自己的 jsonFixer() 函数 - 它分两个步骤工作：删除垃圾（用于不连贯格式的相等性）和重新格式化。
<?php
function jsonFixer($json){
$patterns = [];
/** garbage removal */
$patterns[0] = "/([\s:,\{}\[\]])\s*'([^:,\{}\[\]]*)'\s*([\s:,\{}\[\]])/"; //Find any character except colons, commas, curly and square brackets surrounded or not by spaces preceded and followed by spaces, colons, commas, curly or square brackets...
$patterns[1] = '/([^\s:,\{}\[\]]*)\{([^\s:,\{}\[\]]*)/'; //Find any left curly brackets surrounded or not by one or more of any character except spaces, colons, commas, curly and square brackets...
$patterns[2] = "/([^\s:,\{}\[\]]+)}/"; //Find any right curly brackets preceded by one or more of any character except spaces, colons, commas, curly and square brackets...
$patterns[3] = "/(}),\s*/"; //JSON.parse() doesn't allow trailing commas
/** reformatting */
$patterns[4] = '/([^\s:,\{}\[\]]+\s*)*[^\s:,\{}\[\]]+/'; //Find or not one or more of any character except spaces, colons, commas, curly and square brackets followed by one or more of any character except spaces, colons, commas, curly and square brackets...
$patterns[5] = '/["\']+([^"\':,\{}\[\]]*)["\']+/'; //Find one or more of quotation marks or/and apostrophes surrounding any character except colons, commas, curly and square brackets...
$patterns[6] = '/(")([^\s:,\{}\[\]]+)(")(\s+([^\s:,\{}\[\]]+))/'; //Find or not one or more of any character except spaces, colons, commas, curly and square brackets surrounded by quotation marks followed by one or more spaces and one or more of any character except spaces, colons, commas, curly and square brackets...
$patterns[7] = "/(')([^\s:,\{}\[\]]+)(')(\s+([^\s:,\{}\[\]]+))/"; //Find or not one or more of any character except spaces, colons, commas, curly and square brackets surrounded by apostrophes followed by one or more spaces and one or more of any character except spaces, colons, commas, curly and square brackets...
$patterns[8] = '/(})(")/'; //Find any right curly brackets followed by quotation marks...
$patterns[9] = '/,\s+(})/'; //Find any comma followed by one or more spaces and a right curly bracket...
$patterns[10] = '/\s+/'; //Find one or more spaces...
$patterns[11] = '/^\s+/'; //Find one or more spaces at start of string...
$replacements = [];
/** garbage removal */
$replacements[0] = '$1 "$2" $3'; //...and put quotation marks surrounded by spaces between them;
$replacements[1] = '$1 { $2'; //...and put spaces between them;
$replacements[2] = '$1 }'; //...and put a space between them;
$replacements[3] = '$1'; //...so, remove trailing commas of any right curly brackets;
/** reformatting */
$replacements[4] = '"$0"'; //...and put quotation marks surrounding them;
$replacements[5] = '"$1"'; //...and replace by single quotation marks;
$replacements[6] = '\\$1$2\\$3$4'; //...and add back slashes to its quotation marks;
$replacements[7] = '\\$1$2\\$3$4'; //...and add back slashes to its apostrophes;
$replacements[8] = '$1, $2'; //...and put a comma followed by a space character between them;
$replacements[9] = ' $1'; //...and replace by a space followed by a right curly bracket;
$replacements[10] = ' '; //...and replace by one space;
$replacements[11] = ''; //...and remove it.
$result = preg_replace($patterns, $replacements, $json);
return $result;
}
?>
使用示例：
<?php
// Received badly formatted json:
// {"contact1": "David "Dave" Letterman", price : 30.00, 'details' : "Greatest 'Hits' Album"}
$json_string = '{"contact1": "David "Dave" Letterman", price : 30.00, \'details\' : "Greatest \'Hits\' Album"}';
jsonFixer($json_string);
?>
将导致：
{"contact1": "David \"Dave\" Letterman", "price" : "30.00", "details" : "Greatest \'Hits\' Album"}
注意：这没有使用所有可能的格式错误的 JSON 字符串进行测试，但我在复杂的多级 JSON 字符串上使用，并且在此之前运行良好。