0

如何使用格式通过 *printf() 函数族从输出字符串中删除字符？这是可能的？

从宏这个宏：

  char *s =
    g_strdup_printf(
    "insert into foo(name,serie,"
#define X(a, b) #a ","
    LIST ") "
#undef X
#define X(a, b) "%d,"
    "values('%s'," LIST "%d" ")",
#undef X
#define X(a, b) bol->a,
    boletim->aname, serie, LIST
#undef X
            );

我得到这样的输出：

  char *s =
    g_strdup_printf(
    "insert into foo(name,serie,"

    "red" "," "blue" "," "yellow" "," "purple" "," ") "


    "values('%s'," "%d," "%d," "%d," "%d," "%d" ")",


    boletim->aname, serie, boletim->red, boletim->blue, boletim->yellow, boletim->purple,

      );

puts(s)调用会打印以下内容：

insert into foo(name,serie,red,blue,yellow,purple,) values('Ari tol',-1,-1,-1,-1,0)

但是我有一个问题，,之前的第一个)导致 SQL 查询无效。我正在寻找某种方法将其从字符串中删除。也许通过某种可以在printf()函数族中使用的格式或重新定义宏。我不知道。这只是一个尝试，不要编写)在通过索引调用字符串替换函数之前和之后搜索索引的例程。

4

1 回答 1

1

您不能在预处理器级别删除内容。但是，在这种情况下，您可以定义 X 以将逗号放在每个项目之前，并在“serie”和“'%s'”之后删除逗号。

于 2012-11-05T16:38:03.620 回答