我使用了一个类似的查询
SELECT app_id, SUM(amount), date 
FROM abc 
GROUP BY app_id,date
结果显示如下
1   10   1-2-2000
2   20   1-2-2000
3   30   1-2-2000
1   20   2-2-2000
2   40   2-2-2000
3   50   2-2-2000
我想通过新列获得所需的结果
1   10   1-2-2000
2   30   1-2-2000   # sum of amount of app_id=1 and app_id=2
3   60   1-2-2000   # sum of amount of app_id=1 and app_id=2 and app_id=3
1   20   2-2-2000
2   60   2-2-2000   # sum of amount of app_id=1 and app_id=2
3  110   2-2-2000   # sum of amount of app_id=1 and app_id=2 and app_id=3