c++ - 将我的代码拆分为函数

Question

我需要用 X 标记用户输入的座位，然后用标记的座位再次显示飞机布局（数组）并每次都重复。这是我的代码，我有点卡住了。如果可以的话，请帮我把它分成两个函数：第一个函数应该打印出数组，第二个函数应该接受用户输入并标记座位，然后调用前一个函数来刷新显示。

我的输出应该是这样的：

1 X B C D

2 A X C D

3 A B C D

4 A B X D

5 A B C D

6 A B C D

7 A B C D

我的代码是：

 #include <iostream>

    using namespace std;


    int main ()
    {
        int rowNumber=-1, columnNumber=-1;
        char columnLetter;
        char airplane[7][4] = {{'A', 'B', 'C', 'D'},
         {'A', 'B', 'C', 'D'},
         {'A', 'B', 'C', 'D'},
         {'A', 'B', 'C', 'D'},
         {'A', 'B', 'C', 'D'},
         {'A', 'B', 'C', 'D'},
         {'A', 'B', 'C', 'D'}};

         for (int i=0; i<7; i++)
         { 
             cout<<i+1<<"\t";

             for (int j=0; j<4; j++)
             {
                 cout<<airplane[i][j]<<"\t";   
             }

             cout<<"\n";
         }

       do
       {
       cout<<"Enter row number:"<<endl;
       cin>>rowNumber;
       }while ((rowNumber<1)||(rowNumber>7));

       do
       {
       cout<<"Enter column letter:"<<endl;
       cin>>columnLetter;
       }while (columnLetter!='A'&&columnLetter!='B'&&columnLetter!='C'&&columnLetter!='D');

       if (columnLetter=='A')
       {
          columnNumber=0;
       }
       else if (columnLetter=='B')
       {
          columnNumber=1;
       }
       if (columnLetter=='C')
       {
          columnNumber=2;
       }
       else if (columnLetter=='D')
       {
          columnNumber=3;
       }

       airplane[rowNumber][columnNumber]='X';

           system ("PAUSE");
           return 0;
    }

我试过了，但它没有编译，所以我不能移动到下一个打印标记座位的函数：

#include <iostream>

using namespace std;
void fillArray (char array[][4]);

int main ()
{
   char airplane[7][4] = {{'A', 'B', 'C', 'D'},
     {'A', 'B', 'C', 'D'},
     {'A', 'B', 'C', 'D'},
     {'A', 'B', 'C', 'D'},
     {'A', 'B', 'C', 'D'},
     {'A', 'B', 'C', 'D'},
     {'A', 'B', 'C', 'D'}};

fillArray (airplane[][4]);     


       system ("PAUSE");
       return 0;
}

void fillArray (char array[][4])
{


     for (int i=0; i<7; i++)
     { 
         cout<<i+1<<"\t";

         for (int j=0; j<4; j++)
         {
             cout<<array[i][j]<<"\t";   
         }

         cout<<"\n";
     }
     return;
}

    enter code here

Answer 1

第 16 行应fillArray (airplane);改为fillArray (airplane[][4]);

Answer 2

#include <iostream>

using namespace std;

void fillArray (char array[][4]);
void getSeat (char array[][4]);

int main ()
{
   char airplane[7][4] = {{'A', 'B', 'C', 'D'},
     {'A', 'B', 'C', 'D'},
     {'A', 'B', 'C', 'D'},
     {'A', 'B', 'C', 'D'},
     {'A', 'B', 'C', 'D'},
     {'A', 'B', 'C', 'D'},
     {'A', 'B', 'C', 'D'}};

     fillArray (airplane);
     getSeat (airplane);
     fillArray (airplane);



       system ("PAUSE");
       return 0;
}

void fillArray (char array[][4])
{


     for (int i=0; i<7; i++)
     { 
         cout<<i+1<<"\t";

         for (int j=0; j<4; j++)
         {
             cout<<array[i][j]<<"\t";   
         }

         cout<<"\n";
     }
     return;
}

void getSeat (char array[][4])
{
     int rowNumber=-1, columnNumber=-1;
    char columnLetter;
  do
   {
      cout<<"Enter row number:"<<endl;
      cin>>rowNumber;
      rowNumber=rowNumber-1;
   }while ((rowNumber<1)||(rowNumber>7));

   do
   {
      cout<<"Enter column letter:"<<endl;
      cin>>columnLetter;
   }while (columnLetter!='A'&&columnLetter!='B'&&columnLetter!='C'&&columnLetter!='D');

   if (columnLetter=='A')
   {
      columnNumber=0;
   }
   else if (columnLetter=='B')
   {
      columnNumber=1;
   }
   if (columnLetter=='C')
   {
      columnNumber=2;
   }
   else if (columnLetter=='D')
   {
      columnNumber=3;
   }

   array[rowNumber][columnNumber]='X';
   return;
}