sql - 如何编写返回“介于”的查询以返回字母数据，而不仅仅是数字？

Question

我有一张Daily_account桌子：

customer_id    account_id            current_balance

1                 D1                       200
2                 d2                       300
3                 d10                      400
4                 d100                     500
5                 d101                     600

现在我有一个查询：

select customer_id,account_id,current_balance
from daily_account
where account_id between 'D1' and'D100'

它给了我 D1、D10、D100 账号的输出，但我想得到每个账号的输出。如何获得 D1 和 d100 之间的每个帐户的输出？

Answer 1

经过更多研究后，我发现一个函数是 cast 函数，它给了我答案....

select  customer_id, account_id,current_balance  from daily_account 
where cast(right(Account_id,(length(account_id)-1)) AS unsigned) 
between '1' and'100'

Answer 2

上述代码段中的 between 语句使用的是字符串，这与数字排序不同。

如果 account_id 总是以“D”开头，我们可以将其删除并将其转换为一个数字：

SELECT *
, REPLACE(account_id, 'd','0') // just replace
, CAST( REPLACE(account_id, 'd','0') as int) // now convert to int
FROM daily_account

并在两者之间使用它，像这样使用它

SELECT customer_id,account_id,current_balance
FROM daily_account
WHERE 
CAST( REPLACE(account_id, 'd','0') as int) between 1 and 100

Answer 3

如果一切都以一个字符开始，您可以执行以下操作：

SELECT * FROM (
SELECT customer_id
     , CAST(REPLACE(account_id,'d','') AS int) account_id
     , current_balance
FROM daily_account) tbl
WHERE account_id between '1' and'100'

Answer 4

一个技巧是像这样删除 account_id 中的非数字：

SELECT * FROM Daily_account WHERE CAST(REPLACE(account_id,'D','') AS INT) BETWEEN 1 AND 10

Answer 5

select customer_id,account_id,current_balance
from daily_account
where CAST(replace(account_id, 'D', '') as int) between 1 and 100

Answer 6

您的回答似乎暗示您希望解决方案可以使用各种前缀，而不仅仅是'D'. 如果是这种情况，请考虑以下替代方案：

SELECT customer_id, account_id, current_balance
FROM daily_account
WHERE STUFF(account_id, 1, 1, '') between 1 and 100
;

以上是 SQL Server，但由于您的回答似乎也暗示您正在使用 MySQL，因此这里有一个 MySQL 等价物：

SELECT customer_id, account_id, current_balance
FROM daily_account
WHERE INSERT(account_id, 1, 1, '') between 1 and 100
;