declare
course_id char(10);
course_idA char(10);
cursor task3
is
select c_id from certificationrequirement
where pcp_id = 101;
cursor task3A
is
select o.c_id from courseoffering o
join co_enrolment ce
on o.co_id = ce.co_id
where ce.s_regno = 401 and ce.coe_completionstatus = 'P';
Begin
open task3;
DBMS_OUTPUT.PUT_LINE ( 'List of Course to take ');
loop
FETCH task3 into course_id;
exit when task3%NOTFOUND;
DBMS_OUTPUT.PUT_LINE ( course_id);
end loop;
close task3;
open task3A;
DBMS_OUTPUT.PUT_LINE ( 'List of Courses student has passed ');
loop
FETCH task3A into course_idA;
exit when task3A%NOTFOUND;
DBMS_OUTPUT.PUT_LINE (course_idA);
end loop;
close task3A;
if (cursor task3 = cursor task3A )
Then
DBMS_OUTPUT.PUT_LINE ( 'Student can attempt the Certification exam ');
Else
DBMS_OUTPUT.PUT_LINE ( 'Student cannot attempt the Certification exam ');
END if;
end;
我正在使用一个光标列出学生需要为特定学位学习的所有课程。第二个光标列出学生已经通过了多少门课程以获得他正在学习的学位。如果两个光标中的两个值相等,他将有资格参加退出考试,否则他将无法参加。我已经写下了比较代码,但我认为上面不是正确的方法。