我正在尝试编写一个函数来清理此代码生成的哈希表
/*
* Markov chain random text generator.
*/
#include <string.h>
#include <stdlib.h>
#include <stdio.h>
#include <string.h>
#include <time.h>
#include "eprintf.h"
enum {
NPREF = 2, /* number of prefix words */
NHASH = 4093, /* size of state hash table array */
MAXGEN = 10000 /* maximum words generated */
};
typedef struct State State;
typedef struct Suffix Suffix;
struct State { /* prefix + suffix list */
char* pref[NPREF]; /* prefix words */
Suffix* suf; /* list of suffixes */
State* next; /* next in hash table */
};
struct Suffix { /* list of suffixes */
char* word; /* suffix */
Suffix* next; /* next in list of suffixes */
};
State* lookup(char *prefix[], int create);
void build(char *prefix[], FILE*);
void generate(int nwords);
void add(char *prefix[], char *word);
State* statetab[NHASH]; /* hash table of states */
char NONWORD[] = "\n"; /* cannot appear as real word */
/* markov main: markov-chain random text generation */
int main(void)
{
int i, nwords = MAXGEN;
char *prefix[NPREF]; /* current input prefix */
int c;
long seed;
setProgName("markov");
seed = time(NULL);
srand(seed);
for (i = 0; i < NPREF; i++) /* set up initial prefix */
prefix[i] = NONWORD;
build(prefix, stdin);
add(prefix, NONWORD);
generate(nwords);
return 0;
}
const int MULTIPLIER = 31; /* for hash() */
/* hash: compute hash value for array of NPREF strings */
unsigned int hash(char* s[NPREF])
{
unsigned int h;
unsigned char *p;
int i;
h = 0;
for (i = 0; i < NPREF; i++)
for (p = (unsigned char *) s[i]; *p != '\0'; p++)
h = MULTIPLIER * h + *p;
return h % NHASH;
}
/* lookup: search for prefix; create if requested. */
/* returns pointer if present or created; NULL if not. */
/* creation doesn't strdup so strings mustn't change later. */
State* lookup(char *prefix[NPREF], int create)
{
int i, h;
State *sp;
h = hash(prefix);
for (sp = statetab[h]; sp != NULL; sp = sp->next) {
for (i = 0; i < NPREF; i++)
if (strcmp(prefix[i], sp->pref[i]) != 0)
break;
if (i == NPREF) /* found it */
return sp;
}
if (create) {
sp = (State *) emalloc(sizeof(State));
for (i = 0; i < NPREF; i++)
sp->pref[i] = prefix[i];
sp->suf = NULL;
sp->next = statetab[h];
statetab[h] = sp;
}
return sp;
}
/* addsuffix: add to state. suffix must not change later */
void addsuffix(State *sp, char *suffix)
{
Suffix *suf;
suf = (Suffix *) emalloc(sizeof(Suffix));
suf->word = suffix;
suf->next = sp->suf;
sp->suf = suf;
}
/* add: add word to suffix list, update prefix */
void add(char *prefix[NPREF], char *suffix)
{
State *sp;
sp = lookup(prefix, 1); /* create if not found */
addsuffix(sp, suffix);
/* move the words down the prefix */
memmove(prefix, prefix+1, (NPREF-1)*sizeof(prefix[0]));
prefix[NPREF-1] = suffix;
}
/* build: read input, build prefix table */
void build(char *prefix[NPREF], FILE *f)
{
char buf[100], fmt[10];
/* create a format string; %s could overflow buf */
sprintf(fmt, "%%%ds", sizeof(buf)-1);
while (fscanf(f, fmt, buf) != EOF)
add(prefix, estrdup(buf));
}
/* generate: produce output, one word per line */
void generate(int nwords)
{
State *sp;
Suffix *suf;
char *prefix[NPREF], *w;
int i, nmatch;
for (i = 0; i < NPREF; i++) /* reset initial prefix */
prefix[i] = NONWORD;
for (i = 0; i < nwords; i++) {
sp = lookup(prefix, 0);
if (sp == NULL)
eprintf("internal error: lookup failed");
nmatch = 0;
for (suf = sp->suf; suf != NULL; suf = suf->next)
if (rand() % ++nmatch == 0) /* prob = 1/nmatch */
w = suf->word;
if (nmatch == 0)
eprintf("internal error: no suffix %d %s", i, prefix[0]);
if (strcmp(w, NONWORD) == 0)
break;
printf("%s\n", w);
memmove(prefix, prefix+1, (NPREF-1)*sizeof(prefix[0]));
prefix[NPREF-1] = w;
}
}
这是我到目前为止的清洁功能
/*Clean Function*/
void clean_up(State *sp)
{
State *temp;
Suffix *temp2, temp3;
for(int h = 0; h < NHASH; h++)
{
for (sp = statetab[h]; sp != NULL; sp = sp->next)
{
while(sp->suf != NULL)
{
temp2= sp->suf;
temp3= *temp2->next;
free(temp2);
sp->suf= &temp3;
}
}
}
}
我认为我在正确的轨道上，我正在遍历哈希表中的每个索引，然后从一个状态到另一个状态并释放后缀。我不确定如何处理前缀，因为我必须先释放它们才能释放每个状态。任何帮助将不胜感激。