#include <iostream>
#include <new>
#include <type_traits>
template<typename T, typename U>
struct promote
{
typedef typename std::conditional<(sizeof(T) > sizeof(U)), T, U>::type type;
};
template<class U, class V>
class risk_implementation
{
public:
template<class T>
risk_implementation(T const &t)
{
new(storage_) T(t);
}
//easier to do some test with public
typedef typename promote<U, V>::type Bigger;
typedef typename std::aligned_storage<sizeof(Bigger), alignof(Bigger)>::type storage_type;
storage_type storage_[1];
};
这种实现很丑陋,我不会在实际情况下使用它我只想知道使用像这样的placement new是否安全?谢谢
多亏了你们,我稍微修改了一下密码,现在这样安全吗?