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我正在尝试通过 Google App Engine 进行 HTTPRequest Post。这是我到目前为止所拥有的

URL url = new URL("http://myurl.com/myfile.php");
HTTPRequest request = new HTTPRequest(url, HTTPMethod.POST);
request.setPayload(########);
HTTPResponse response = URLFetchServiceFactory.getURLFetchService().fetch(request);

在这里我需要放置一些配对值（即“email”、“hi@example.com”等） 因为 setPayload 接受 byte[] 我不知道如何将配对值转换为字节。

我已经搜索了其他帖子，但我非常卡住。

编辑：我已更改为此，但仍然无法正常工作

byte[] data = ("EMAIL=bo0@gmail.com&TITLE=evolution&COMMENT=comments&PRICE=5000;").getBytes();
try {
URL url = new URL("http://www.bo.x10.mx/nPost.php");
HTTPRequest request = new HTTPRequest(url, HTTPMethod.POST);
request.setPayload(data);
HTTPResponse response = URLFetchServiceFactory.getURLFetchService().fetch(request);

这就是我在 php 网站上的内容。

<?php
include "path/conf.php"; //logging into database works
$tb_name = 'Post';
$EMAIL=$_POST['EMAIL'];
$TITLE =$_POST['TITLE'];
$COMMENT =$_POST['COMMENT'];
$PRICE =$_POST['PRICE'];
if(!isset($EMAIL) || !isset($TITLE ) || !isset($PRICE )|| !isset($COMMENT)){
header('HTTP/1.0 412 Precondition Failed', true, 412);
die('Bad data');
}
$sql="INSERT INTO $tb_name(EMAIL, TITLE, COMMENT, PRICE) VALUES ('$EMAIL', '$TITLE ', '$COMMENT ', '$PRICE ')";
$result=mysql_query($sql);
if($result==TRUE){
echo "successfully inserted into table!";}
else{
echo "error in inserting into table!";
header('HTTP/1.0 500 Internal Server Error', true, 500);}
ob_end_flush();
exit();
?>

EDIT2：这是一个工作代码

try{
byte[] data = ("EMAIL=bo0@gmail.com&TITLE=evolution&COMMENT=comments&PRICE=5000").getBytes("UTF-8");
URL url = new URL("http://www.box.com/nost.php");
HTTPRequest request = new HTTPRequest(url, HTTPMethod.POST);
request.setPayload(data);
HTTPResponse response = URLFetchServiceFactory.getURLFetchService().fetch(request);
}

我的数据库字符串字段是 UTF-8 类型

4

1 回答 1

4

您使用请求正文创建一个String，然后获得字节数组。例如我们有：

URL url = new URL("http://myurl.com/myfile.php");
HTTPRequest request = new HTTPRequest(url, HTTPMethod.POST);
String body = "email=" + email + "&mpla=" + mpla;
request.setPayload(body.getBytes("UTF-8"));
HTTPResponse response = URLFetchServiceFactory.getURLFetchService().fetch(request);

希望这可以帮助！

于 2012-11-04T08:45:26.560 回答