6

我正在尝试扩展app.get行为，但似乎在这样做之后，该应用程序丢失了我在扩展它之前所做的一些配置。

在以下代码段中，/sample和/es/sample输出为空，预期输出应为“value”

难道我做错了什么？

var app = require('express')();

app.set('myprop', 'value');

var _get = app['get'];

app['get'] = function (route, middleware, callback) {
    _get.call(app, route, middleware, callback);

    // For instance: I generate a new route for 'es' language.
    _get.call(app, '/es' + route, middleware, callback);
};

app.get('/sample', function(req, res){
    res.send(app.get('myprop'));
});

app.use(app.router);
app.listen(3000);

更新

对不起，我会回答自己...

我错过了扩展方法中的以下第一行:)

if (middleware === undefined && callback === undefined) return _get.call(app, route);

现在它就像一个魅力！

app['get'] = function (route, middleware, callback) {
    if (middleware === undefined && callback === undefined) return _get.call(app, route);
    _get.call(app, route, middleware, callback);

    // For instance: I generate a new route for 'es' language.
    _get.call(app, '/es' + route, middleware, callback);
};
4

1 回答 1

1

在您的代码中，您app.get使用一个参数破坏了行为。试试这个：

var app = require('express')();

app.set('myprop', 'value');

var _get = app['get'];

app['get'] = function (route, middleware, callback) {
    if (arguments.length > 1) {
        _get.call(app, route, middleware, callback);

        // For instance: I generate a new route for 'es' language.
        _get.call(app, '/es' + route, middleware, callback);
    } else {
        return _get.apply(app, arguments);
    }
};

app.get('/sample', function(req, res){
    res.send(app.get('myprop'));
});

app.use(app.router);
app.listen(3000);
于 2012-11-03T16:50:52.743 回答