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我有 2 个具有相同列的表，我需要从两个表中全部显示它们，但现在我得到每行中的所有列，例如。定位器每行 2 次，它必须从正确的表中仅显示 1 次。

SELECT a.*, b.* FROM  clothes a, items b group by a.locator,b.locator

我该怎么做呢？

我将让它从两个带有行的表中输出。“名称”、“定位器”、“价格”和 WHERE “ibutik” = 1。

带有测试行的衣服表：

   CREATE TABLE IF NOT EXISTS `clothes` (
   `id` int(11) NOT NULL AUTO_INCREMENT,
   `locator` varchar(48) DEFAULT NULL,
   `name` varchar(32) DEFAULT NULL,
     `price` int(11) DEFAULT '100',
    `level` smallint(6) DEFAULT '0',
     `type` smallint(6) DEFAULT NULL,
     `sex` smallint(4) DEFAULT NULL,
     `x_offset` smallint(6) DEFAULT '0',
     `y_offset` smallint(6) DEFAULT '0',
     `nontradeable` tinyint(4) DEFAULT '0',
     `ibutik` int(1) NOT NULL,
     `koebt` int(9) NOT NULL,
     PRIMARY KEY (`id`)
   ) ENGINE=MyISAM  DEFAULT CHARSET=utf8 AUTO_INCREMENT=55 ;


 INSERT INTO `clothes` (`id`, `locator`, `name`, `price`, `level`, `type`, `sex`, `x_offset`, `y_offset`, `nontradeable`, `ibutik`, `koebt`) VALUES
   (1, '1.png', 'Male body', 100, 1, 2, 1, 0, 0, 0, 0, 0),
   (3, '1.png', 'Female body\r\n', 100, 1, 1, 2, 0, 0, 0, 0, 0))

和项目：

CREATE TABLE IF NOT EXISTS `items` (
      `id` int(11) NOT NULL AUTO_INCREMENT,
  `locator` varchar(32) DEFAULT '',
  `name` varchar(32) DEFAULT '',
  `price` int(11) DEFAULT '100',
  `level` smallint(6) DEFAULT '0',
  `rotateable` tinyint(4) DEFAULT '0',
  `x_offset` smallint(6) DEFAULT '0',
  `y_offset` smallint(6) DEFAULT '0',
  `z_index` smallint(6) DEFAULT '0',
  `nontradeable` tinyint(4) DEFAULT '0',
  `ibutik` int(1) NOT NULL,
  PRIMARY KEY (`id`)
) ENGINE=MyISAM  DEFAULT CHARSET=utf8 AUTO_INCREMENT=20 ;



INSERT INTO `items` (`id`, `locator`, `name`, `price`, `level`, `rotateable`, `x_offset`, `y_offset`, `z_index`, `nontradeable`, `ibutik`) VALUES
(1, 'rodplante.png', 'Rød plante', 10, 0, 0, 0, 0, 0, 0, 1),
(2, '1.png', 'Gul plante', 0, 0, 0, 0, 0, 0, 0, 0),
(3, '2.png', 'Gul plante', 0, 0, 0, 0, 0, 0, 0, 0),
4

1 回答 1

1

在可以尝试类似的东西：

select id,locator,name,price, tableName from 
(
  select a.id as id, a.locator as locator, a.name as name, 
     a.price as price, a.ibutik as ibutik, 'closes' as tableName 
    from  clothes a
  union all
  select b.id,b.locator,b.name,b.price,b.ibutik,'items' from items b 
) foo
where ibutik=0;

用sqlFiddle验证。

于 2012-11-03T09:22:10.453 回答