5

我有以下查询：

-- CTE to remove outliers, e.g. remove the fastest and slowest results
;WITH MinMaxCTE AS 
(
  SELECT ServerName, CONVERT(VARCHAR(10), UpdatedOn, 101) AS [Date], Version, 
    MIN(JaguarStartupTime) AS MinStartTime, MAX(JaguarStartupTime) AS MaxStartTime
  FROM dbo.MachineConfiguration (NOLOCK)
  WHERE DomainLogin NOT IN (SELECT DomainLogin FROM dbo.SupportGroup)
  GROUP BY ServerName, CONVERT(VARCHAR(10), UpdatedOn, 101), Version
)

SELECT  AVG(mc.JaguarStartupTime) AS AverageTime
    , COUNT(*) AS NumEntries
    , mc.Version
FROM    #Eligible mc (NOLOCK)
JOIN MinMaxCTE cte ON mc.ServerName = cte.ServerName 
  AND CONVERT(VARCHAR(10), mc.UpdatedOn, 101) = cte.[Date] 
  AND mc.Version = cte.Version 
  AND mc.JaguarStartupTime <> cte.MinStartTime 
  AND mc.JaguarStartupTime <> cte.MaxStartTime
GROUP BY mc.Version
ORDER BY Version DESC, AVG(mc.JaguarStartupTime) ASC

#Eligible 临时表的定义是

create table #Eligible (
    Version nvarchar(50), JaguarStartupTime int, 
    ServerName nvarchar(50), UpdatedOn datetime )

无论我注释掉什么条件或聚合，我总是收到以下错误：Arithmetic overflow error converting expression to data type int.

我可以从这里去哪里？我该如何进一步调试？

编辑：样本数据

Version JaguarStartupTime    ServerName     UpdatedOn
6.4.6.082      16040         NewOrleansLA   2012-08-08 12:34:12.330
6.5.1.012      40390         BatonRougeLA   2012-08-08 18:33:17.440
6.5.1.012      48379         HonoluluHI     2012-08-09 04:42:50.453
4

1 回答 1

5

您是否尝试过将您的 jaguarstartup 时间转换为您的 avg 聚合中的 bigint，就像这样...

AVG(CAST(mc.JaguarStartupTime AS BIGINT))

这应该解决算术溢出问题。

要计算平均平均值，服务器需要能够首先对所有整数求和，因此您要平均的数据类型需要能够存储这些值的总和，即使返回的答案在整数的范围内

于 2012-11-02T18:02:19.407 回答