我有 3 个查询,我希望使用 array_merge 和 array_unique 将所有结果都放在一个结果中。
这是查询:
$query1 = mysql_query("SELECT * FROM prereservation where '$arival' BETWEEN arrival and departure and room_id ='11' and status = 'active'");
while($rows1 = mysql_fetch_assoc($query1)){
echo $rows1['id']. " - ". $rows1['qty'];
echo "<br />";
}
$query2 = mysql_query("SELECT * FROM prereservation where '$departure' BETWEEN arrival and departure and room_id ='11' and status = 'active'");
while($rows2 = mysql_fetch_assoc($query2)){
echo $rows2['id']. " - ". $rows2['qty'];
echo "<br />";
}
$query3 = mysql_query("SELECT * FROM prereservation where arrival > '$arival' and departure < '$departure' and room_id ='11' and status = 'active'");
while($rows3 = mysql_fetch_assoc($query3)){
echo $rows3['id']. " - ". $rows3['qty'];
echo "<br />";
}
example result is:
for $rows1 | $rows2 | $rows3
id | qty | id | qty | id | qty
-----|--------|-------|--------|-------|------
01 | 1 | 01 | 1 | 02 | 1
03 | 1 | 02 | 1 | 03 | 1
04 | 1 | 03 | 1 | 04 | 1
08 | 1 | 05 | 1 | 05 | 1
我不知道这是否正确?
$sample = array_unique(array_merge($rows1['id'], $rows2['id'], $rows3['id']))
我想为每个结果的 id 使用 array_merge 和 array_unique,所以将留下的 id 的最终结果是
01, 02, 03, 04, 05, 08.
对于下一个查询,我想要的是这些 id 的总和(数量)。但我不知道如何为此编写查询,这是我的示例:
$query = mysql_query("SELECT sum(qty) FROM prereservation where id = $sample");
while($rows = mysql_fetch_array($query))
{
$total_qty = $rows['sum(qty)'];
}
所以总和(数量)等于6。请纠正我的编码错误,谢谢大家...
最后我找到了解决方案,在这里..
$a = $p['id'];
$query1 = mysql_query("SELECT DISTINCT id, SUM(qty)
FROM prereservation
WHERE
(
( '$arival1' BETWEEN arrival AND departure ) OR
( '$departure1' BETWEEN arrival AND departure ) OR
( arrival > '$arival1' AND departure < '$departure1' )
)
AND room_id ='$a'
AND STATUS = 'active'");
while($rows1 = mysql_fetch_assoc($query1)){
$set1 = $rows1['SUM(qty)'];
}
?>
<select id="select" name="qty[]" style=" width:50px;" onchange="checkall()">
<option value="0"></option>
<? $counter = 1; ?>
<? while ($counter <= ($p['qty']) - $set1){ ?>
<option value="<?php echo $counter ?>"><?php echo $counter ?></option>
<? $counter++;
}?>
</select>
解决方案是结合你所有的答案,谢谢你们..