2

这是一个非常有趣的问题......我正在编写一个程序来通过 SQLAlchemy 操作具有相同模式的多个远程数据库。连接字符串不是静态的——它存储在本地 SQLite 数据库中。我需要在运行时创建一个会话,并使用该会话来反映数据库模式。所有数据库都有相同的模式。我已经知道表名。无论如何要实现这个?

def connect(connstr):
    engine = create_engine(connstr)
    metadata = MetaData(bind=engine)
    session = create_session(bind=engine)
    return session

class User(Base):
    # How it's possible to create a dummy model class without predefined metadata?
    __table__ = Table('users', metadata, autoload=True)

编辑:最后我自己解决了这个问题:

Base = declarative_base()

def connect(connstr):
    engine = create_engine(connstr)
    metadata = MetaData(bind=engine)
    session = create_session(bind=engine)
    return metadata, session

def get_model(metadata, modelname, tablename):
    cls = type(modelname, (Base,), dict(
        __table__ = Table(tablename, metadata, autoload = True)
    ))
    return cls

但是,@Gary van der Merwe 的回答非常酷!

4

1 回答 1

3

您必须手动将 orm 类映射到反射表。

假设数据库具有以下结构:

CREATE TABLE "group" (
        id INTEGER NOT NULL, 
        name VARCHAR(50), 
        PRIMARY KEY (id)
)

CREATE TABLE user (
        id INTEGER NOT NULL, 
        name VARCHAR(50), 
        password VARCHAR(12), 
        group_id INTEGER, 
        PRIMARY KEY (id), 
        FOREIGN KEY(group_id) REFERENCES "group" (id)
)

你可以做:

#!/usr/bin/env python

from sqlalchemy import create_engine, MetaData
from sqlalchemy.orm import mapper, Session, relationship


class Group(object):
    def __init__(self, name):
        self.name = name

class User(object):
    def __init__(self, name, password, group):
        self.name = name
        self.password = password
        self.group = group

    group = relationship(Group)

def connect(url):
    engine = create_engine(url, echo=True)
    metadata = MetaData(engine, reflect=True)

    # Do this for each table
    mapper(User, metadata.tables['group'])
    mapper(Group, metadata.tables['user'])


    session = Session(bind=engine)
    return session


session = connect('sqlite:///test.db')
finance_group = Group('finance')
session.add(finance_group)
session.add(User('joe', 'password', finance_group))
session.commit()
print(session.query(User).all())
于 2012-11-02T09:30:30.510 回答