我有一个奇怪的问题。
我正在编写一个简单的数独程序。现在一切正常，除了这个方法：
public static void checkAnswerKey()
{
int rowCounter = 0;
int columnCounter = 0;
System.out.println("The answers that are correct are (F is incorrect): ");
for (rowCounter = 0; rowCounter <= 8; rowCounter += 1)
{
for (columnCounter = 0; columnCounter <= 8; columnCounter += 1)
{
if (gui.userInputFormattedArray[rowCounter][columnCounter].getText() == io.puzzleAnswerArray[rowCounter][columnCounter].toString())
{
gui.userInputFormattedArray[rowCounter][columnCounter].setBackground(gui.correctAnswer);
System.out.print(gui.userInputFormattedArray[rowCounter][columnCounter].getText() + " ");
}
else
{
gui.userInputFormattedArray[rowCounter][columnCounter].setBackground(gui.incorrectAnswer);
System.out.print(gui.userInputFormattedArray[rowCounter][columnCounter].getText() + io.puzzleAnswerArray[rowCounter][columnCounter].toString() + " ");
//System.out.print("F" + " ");
}
}
System.out.println();
}
这取自 game.java 文件。
现在，这个方法应该根据内部答案检查用户输入。它确实如此。但一切都变得不正确。
以下是 io.java 和 gui.java 文件中的声明/实例化。
public class gui extends JFrame implements ActionListener{
...
public static JFormattedTextField[][] userInputFormattedArray = new JFormattedTextField[9][9];
//Create the container.
public Container pane = getContentPane();
//The font the game uses.
public Font gameFont = new Font("Arial", Font.PLAIN, 30);
//Correct and incorrect answer colors.
static Color correctAnswer = new Color(100, 255, 100);
static Color incorrectAnswer = new Color(255, 100, 100);
这两个方法在构造函数中启动：
public void showTextFields()
{
int rowCounter = 0;
int columnCounter = 0;
for (rowCounter = 0; rowCounter <= 8; rowCounter += 1)
{
for (columnCounter = 0; columnCounter <= 8; columnCounter += 1)
{
userInputFormattedArray[rowCounter][columnCounter] = new JFormattedTextField();
pane.add(userInputFormattedArray[rowCounter][columnCounter]);
userInputFormattedArray[rowCounter][columnCounter].setFont(gameFont);
userInputFormattedArray[rowCounter][columnCounter].setHorizontalAlignment(JTextField.CENTER);
}
}
}
public void setTextFields()
{
String heldString;
boolean notEditable = false;
int rowCounter = 0;
int columnCounter = 0;
for (rowCounter = 0; rowCounter <= 8; rowCounter += 1)
{
for (columnCounter = 0; columnCounter <= 8; columnCounter += 1)
{
if (game.puzzleUserShownArray[rowCounter][columnCounter] != 0)
{
heldString = game.puzzleUserShownArray[rowCounter][columnCounter].toString();
userInputFormattedArray[rowCounter][columnCounter].setText(heldString);
userInputFormattedArray[rowCounter][columnCounter].setEditable(notEditable);
}
}
}
}
这就是答案的来源：
public static Integer[][] puzzleAnswerArray = new Integer[9][9];
public void getPuzzle() throws FileNotFoundException
{
Scanner puzzlesInFile = new Scanner(new FileReader("C:\\Users\\owner\\Desktop\\eclipse\\projects\\Sudoku\\Sudoku\\src\\puzzles.dat"));
String searchParameter = "#puzzle" + intPuzzleSeed;
int rowCounter = 0;
int columnCounter = 0;
//Prints the search parameter into the console, ensuring accuracy with the RNG.
System.out.print(searchParameter);
System.out.println();
//
puzzlesInFile.findWithinHorizon(searchParameter, 0);
while (puzzlesInFile.hasNextInt())
{
for (rowCounter = 0; rowCounter <= 8; rowCounter += 1)
{
for (columnCounter = 0; columnCounter <= 8; columnCounter += 1)
{
puzzleAnswerArray[rowCounter][columnCounter] = puzzlesInFile.nextInt();
System.out.print(puzzleAnswerArray[rowCounter][columnCounter].toString() + " ");
}
System.out.println();
}
}
puzzlesInFile.close();
}
我希望这是足够的信息。我错过了一些明显的东西吗？顺便说一下，这是一个已完成拼图的控制台输出：
正确答案是（F 不正确）： 11 22 33 44 55 66 77 88 99 44 55 66 77 88 99 11 22 33 77 88 99 11 22 33 44 55 66 22 33 44 55 66 77 88 99 11 55 66 77 88 99 11 22 33 44 88 99 11 22 33 44 55 66 77 33 44 55 66 77 88 99 11 22 66 77 88 99 11 22 33 44 55 99 11 22 33 44 55 66 77
这是图形用户界面：
---编辑：我无法发布 GUI，因为我的声望少于 10。一旦我到达那里，我将发布一个 GUI 的 .png 文件。---
我的猜测是，即使“字符串”是相同的，但由于某种原因，它并不认为它是相同的。如果您需要查看更多代码，请告诉我，但我想我涵盖了所有内容。