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程序要求用户输入一系列字符串（他们的名字和一个 8 个字母的单词），打印他们的名字，单词的第一个和最后三个字母，然后向后打印他们的单词。需要 for 循环的帮助才能向后显示字符串。

    #include <iostream> 

int main () { 


string FirstName; 

string LastName; 

string MiddleName; 

string Names; 

string string1; 

int len; 

int x;  

 cout << "Hello. What is your first name?" << endl; 

 cin >> FirstName; 

 cout << FirstName  << ", what is your last name?" << endl; 

 cin >> LastName; 

 cout << "And your middle name?" << endl; 

 cin >> MiddleName; 

 Names = LastName + ", " + FirstName + ", " + MiddleName; 

 cout << Names << endl; 

 cout << "Please enter a word with 8 or more characters (no spaces): " << endl; 

 cin >> string1; 

 len = string1.length(); 

   if (len < 8){
     cout << "Error. Please enter a word with 8 or more characters and no spaces: " <<    endl; 

     cin >> string1; 
 }

  else if (len >= 8){

     cout << "The word you entered has " << string1.length() << " characters."<<endl; 

 cout << "The first three characters are " << string1.substr(0,3) << endl; 

 cout << "The last three characters are " <<string1.substr(string1.length()-3,3) << endl; 

x = string1.length()-1; 

for (x = string1.length()-1; x >=0; x--){
 cout << "Your word backwards: " << string1[x]; 
}
}



return 0; 
}
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4 回答 4

5

你几乎在那里：

cout << "Your word backwards: ";
for (x = string1.length()-1; x >=0; x--){
   cout << string1[x]; 
}

这样，循环将以string1相反的顺序打印每个字符，并且"Your word backwards: "仅打印一次文本。

于 2012-11-01T21:30:00.517 回答
1

如果你想变得花哨：

copy(string1.rbegin(), string1.rend(), ostream_iterator<char>(cout));
于 2012-11-01T21:36:51.707 回答
0

一种简单的方法是将字符串从反向存储在临时数组中，然后使用此临时数组打印反向字符串。例如：- temp[j--]=str[i ++] ；在一个循环中。但在此之前要小心，将数组“temp”的大小初始化为原始数组的大小。在这种情况下，这里是“str”。

于 2012-11-01T21:33:24.057 回答
0

这可能不是您问题的答案，但我会选择其中之一：

std::cout << "Your word backwards: "
          << std::string(string1.rbegin(), string1.rend()) << '\n';

*std::copy(string1.rbegin(), string1.rend(),
           std::ostreambuf_iterator<char>(std::cout << "Your word backwards: "))++ = '\n';

std::reverse(string1.begin(), string1.end());
std::cout << "Your word backwards: " << string1 << '\n';
于 2012-11-01T21:37:00.583 回答