java - 友好的 URL 映射问题 - Java Spring

Question

我在 web.xml 上遇到错误，所有页面都显示为 404，可能有根路径，但我无法确定它的设置位置等。

这是我当前的 web.xml

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" id="WebApp_ID" version="2.5">
  <display-name>Spring3MVC</display-name>
  <welcome-file-list>
    <welcome-file>index.jsp</welcome-file>
  </welcome-file-list>
  <servlet>
    <servlet-name>spring</servlet-name>
    <servlet-class>
                  org.springframework.web.servlet.DispatcherServlet
              </servlet-class>
    <load-on-startup>1</load-on-startup>
  </servlet>
  <servlet-mapping>
    <servlet-name>spring</servlet-name>
    <url-pattern>/*</url-pattern>

  </servlet-mapping>
</web-app>

我的监听控制器是这样的

/*
 * User
*/
@RequestMapping(value={"/user/{id}"}, method=RequestMethod.GET)
public ModelAndView profileDisplay(
        HttpServletRequest request, 
        HttpServletResponse response,
        @RequestParam(value="id", required=false) String id
) throws UnknownHostException, MongoException {
    ServiceSerlvet.appendSesssion(request);
    //get search ALL users
    BasicDBObject searchQuery = new BasicDBObject();
        searchQuery.put("_id", new ObjectId(id));
    List<DBObject> searchResponse = PersonController.searchUsers(searchQuery);      

    //System.out.println("response from search user method: "+searchResponse);

        return new ModelAndView("user", "people", searchResponse);
}

这是当前出现的错误。为什么它没有映射，我该如何解决这个问题？

INFO: Server startup in 5904 ms
01-Nov-2012 19:40:21 org.springframework.web.servlet.DispatcherServlet noHandlerFound
WARNING: No mapping found for HTTP request with URI [/springApp21] in DispatcherServlet with name 'spring'
01-Nov-2012 19:40:22 org.springframework.web.servlet.mvc.support.DefaultHandlerExceptionResolver handleNoSuchRequestHandlingMethod
WARNING: No matching handler method found for servlet request: path '/user', method 'GET', parameters map['id' -> array<String>['4fa6eddc0234964172522248']]
01-Nov-2012 19:40:24 org.springframework.web.servlet.mvc.support.DefaultHandlerExceptionResolver handleNoSuchRequestHandlingMethod
WARNING: No matching handler method found for servlet request: path '/user', method 'GET', parameters map['id' -> array<String>['4fa6eddc0234964172522248']]

Answer 1

我事先回答了你的一个问题。我现在可以访问我的一个 spring 应用程序。这是一个更好的配置。

请注意对 web.xml 的更改，我很抱歉，但映射到 /* 会导致您的所有请求都由调度程序解决。从某种意义上说，您创建了一个循环，您的初始映射将由调度程序转发到控制器，然后控制器将使用视图解析器映射您的请求应转发到的位置。映射到 /* 会导致视图解析器映射由调度程序处理。

更改为 / 会导致所有未映射的 url 由调度程序处理，因此您的初始映射由调度程序处理，调度程序将其发送到控制器，并且由您的 viewresolver 创建的映射将映射到 .jsp 导致它不会被拾取由调度员上来。我很抱歉。

Web.xml

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" id="WebApp_ID" version="2.5">
  <display-name>Spring3MVC</display-name>
  <welcome-file-list>
    <welcome-file>index.jsp</welcome-file>
  </welcome-file-list>
  <servlet>
    <servlet-name>spring</servlet-name>
    <servlet-class>
                  org.springframework.web.servlet.DispatcherServlet
              </servlet-class>
    <load-on-startup>1</load-on-startup>
  </servlet>
  <servlet-mapping>
    <servlet-name>spring</servlet-name>
    <url-pattern>/</url-pattern>

  </servlet-mapping>
</web-app>

spring-config.xml（必须更改组件扫描）

<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/mvc"
    xmlns:beans="http://www.springframework.org/schema/beans"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns:context="http://www.springframework.org/schema/context"
    xsi:schemaLocation="http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.1.xsd
        http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
        http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.1.xsd">

    <!-- DispatcherServlet Context: defines this servlet's request-processing infrastructure -->

    <!-- Enables the Spring MVC @Controller programming model -->   
    <annotation-driven/>

        <!-- Handles HTTP GET requests for /resources/** by efficiently serving up static resources in the ${webappRoot}/resources directory -->
    <resources location="/resources/" mapping="/resources/**"/> 

    <!-- Resolves views selected for rendering by @Controllers to .jsp resources in the /WEB-INF/views directory -->
    <beans:bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
        <beans:property name="prefix" value="/WEB-INF/views/"/>
        <beans:property name="suffix" value=".jsp"/>
    </beans:bean>

    <context:component-scan base-package="package.with.controllers" />

</beans:beans>

控制器

@RequestMapping(value={"/user/{id}"}, method=RequestMethod.GET)
public ModelAndView profileDisplay(
        HttpServletRequest request, 
        HttpServletResponse response,
        @RequestParam(value="id", required=false) String id
) throws UnknownHostException, MongoException {
    ServiceSerlvet.appendSesssion(request);
    //get search ALL users
    BasicDBObject searchQuery = new BasicDBObject();
        searchQuery.put("_id", new ObjectId(id));
    List<DBObject> searchResponse = PersonController.searchUsers(searchQuery);      

    //System.out.println("response from search user method: "+searchResponse);

        //This should display "WEB-INF/views/user.jsp" you may need to adjust.
        return new ModelAndView("user", "people", searchResponse);
}

Answer 2

谢谢Kbm回到我身边。我已经更改了我的 web.xml，并且一般映射已经解决。我遇到了你提到的 css、js、图像文件也通过的问题。

我试图添加拦截网址，但有些东西仍然无法正常工作。http 在 web.xml 中以红色突出显示。当我在日食中将鼠标悬停在它上面时，它表示

cvc-complex-type.2.4.a：发现以元素“http”开头的无效内容。'{"http://java.sun.com/xml/ns/javaee":description, "http://java.sun.com/xml/ns/javaee":display-name, "http:// /java.sun.com/xml/ns/javaee":icon, "http://java.sun.com/xml/ns/javaee":distributable, "http://java.sun.com/xml/ns /javaee":context-param, "http://java.sun.com/xml/ns/javaee":filter, "http://java.sun.com/xml/ns/javaee":filter-mapping, “http://java.sun.com/xml/ns/javaee”：监听器，“http://java.sun.com/xml/ns/javaee”：servlet，“http://java.sun.com /xml/ns/javaee":servlet-mapping, "http://java.sun.com/xml/ns/javaee":session-config, "http://java.sun.com/xml/ns/javaee ":mime-mapping, "http://java.sun.

web.xml

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" id="WebApp_ID" version="2.5">
  <display-name>Spring3MVC</display-name>
  <welcome-file-list>
    <welcome-file>index.jsp</welcome-file>
  </welcome-file-list>
  <servlet>
    <servlet-name>spring</servlet-name>
    <servlet-class>
                  org.springframework.web.servlet.DispatcherServlet
              </servlet-class>
    <load-on-startup>1</load-on-startup>
  </servlet>
  <servlet-mapping>
    <servlet-name>spring</servlet-name>
    <url-pattern>/</url-pattern>
  </servlet-mapping>

  <http auto-config='true'>
   <intercept-url pattern="/css/**" filters="none"  />
    <intercept-url pattern="/images/**" filters="none" />
    <intercept-url pattern="/js/**" filters="none" />
  </http>
</web-app>