python - 打印 1 到 10 之间的随机数并在数字为 N 时停止的 While 循环

Question

这就是我所拥有的，但这只会生成一个随机数并无限打印该数字：

import random

x = random.randint(0,10)
y = 7
while x != y:
    print(x)

Answer 1

类似的东西（在while内移动条件）：

stop_at = 7
while True:
    num = random.randint(0, 10)
    if num == stop_at:
        break
    print num

或者，一个完整的重构：

from itertools import starmap, repeat, takewhile
from random import randint

for num in takewhile(lambda L: L != 7, starmap(randint, repeat( (0, 10) ))):
    print num

Answer 2

你几乎得到它，你需要在循环内生成一个新的随机数：

import random

x = random.randint(0,10)
y = 7
while x != y:
    print(x)   #Print old (non-7) random number
    x = random.randint(0,10)  #pick a new number.  I hope it's 7 so we can end this madness

print("You found {0}.  Congrats.  Go have a beer.".format(y))