3

我有一个要求输入的脚本，然后将该输入插入到表中。下次运行脚本时，我希望它告诉用户最后输入的 id 是什么。

该表如下所示： id INTEGER PRIMARY KEY AUTOINCREMENT, userid TEXT, domain TEXT, password TEXT, webserver TEXT, sqlserver TEXT

有人告诉我可以使用 SELECT seq from SQLITE_SEQUENCE WHERE name='table_name' 但它会产生以下文本：而不是最后一行的 id。

请注意，我是一个非常新的 Python / SQLite3 编码器！

供您参考，到目前为止的代码如下所示：

#!/usr/bin/python
import os, sys, sqlite3
######## CHECK SYSTEM COMPATIBILITY ########
if os.name =='posix':
    os.system("clear")#CLEAR SCREEN#
    pass
else:
    sys.exit("Operating System is not supported")
######## END CHECK SYSTEM COMPATIBILITY ########
######## CHECK IF SCRIPT IS RUN AS ROOT ########
#if os.geteuid() != 0:
#       sys.exit("Script must be run as root")
#else:
#       pass
####### END CHECK IF SCRIPT IS RUN AS ROOT ########
####### CREATE DATABASE AND CHECK IF TABLE EXISTS ##########
conn = sqlite3.connect("dat.db")
c = conn.cursor()
c.execute ('''CREATE TABLE IF NOT EXISTS kunder
            (id INTEGER PRIMARY KEY AUTOINCREMENT, userid TEXT, domain TEXT, password      TEXT, webserver TEXT, sqlserver TEXT)''')
conn.commit()
print c.execute ("SELECT seq from SQLITE_SEQUENCE WHERE name='kunder'")
conn.close()
######## DONE CREATE DATABASE AND CHECK IF TABLE EXISTS #########
###### ASK FOR INPUT ##########
########### HERE NEEDS TO BE A CHECK TO DETERMINE THE LATEST USERID - ALSO NEEDS TO BE    FOR WEBSERVER AND PASSWORD #################
userid = raw_input("Enter userid: ")
########### HERE NEEDS TO BE A CHECK TO SEE IF USERID EXISTS!!!!!#####################
domain = raw_input("Enter domain: ")
password = raw_input("Enter password: ")
########### NEEDS TO BE A WAY TO AUTOGENERATE A PASSWORD!!! ####################
webserver = raw_input("Enter webserver: ")
sqlserver = raw_input("Enter sqlserver: ")
###### FINISHED ASK FOR INPUT #######
######## DATABASE ###########
conn = sqlite3.connect("dat.db")
c = conn.cursor()
c.execute ("INSERT INTO kunder (userid, domain, password, webserver, sqlserver) VALUES    (?,?,?,?,?)", (userid, domain, password, webserver, sqlserver))
conn.commit()
conn.close()
####### DONE WITH DATABASE ##########
4

3 回答 3

5

The SQL statement SELECT max(id) FROM table_name should give you the maximum id. If you're auto-incrementing then this would be the same as the last inserted.

Edit: To get the actual value in python means reading it from the cursor:

cursor = sqlite3.execute('SELECT max(id) FROM table_name')
max_id = cursor.fetchone()[0]

fetchone() returns the first row from the select statement as a tuple (unless a row_factory is used), so fetchone()[0] will, in this case, return the first (and only) column in the first (and only) row, i.e. the max(id).

See http://docs.python.org/2/library/sqlite3.html for more info.

于 2012-11-01T12:57:03.927 回答
2

尝试使用sqlite3_last_insert_rowid()

于 2012-11-01T12:54:18.660 回答
0 
import sqlite3

data_person_name = [('Michael', 'Fox'),
                    ('Adam', 'Miller'),
                    ('Andrew', 'Peck'),
                    ('James', 'Shroyer'),
                    ('Eric', 'Burger')]

con = sqlite3.connect(":memory:")
c = con.cursor()

c.execute('''CREATE TABLE q1_person_name
             (name_id INTEGER PRIMARY KEY,
              first_name varchar(20) NOT NULL,
              last_name varchar(20) NOT NULL)''')

for data_person in data_person_name:
    c.execute('INSERT INTO q1_person_name(first_name, last_name) VALUES (?,?)', data_person)
    # get the last rowid inserted
    last_name_id = c.lastrowid
    print(last_name_id)
于 2019-07-04T21:34:49.990 回答