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我是android新手，请任何人都可以在这里帮助我，如何从只有注册用户才能登录的网站数据库中验证用户名和密码。如何从我的网站获取特定内容并将其显示在 android 应用程序中。

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3 回答 3

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在应用程序中查看有两种类型的验证

1. Client side validation and 2. Server side validation

在这里，您询问Android App的服务器端登录身份验证。请参考此链接，这是您找到的很好的解决方案。在本教程中准确描述了您搜索的内容。

于 2012-11-01T10:53:28.470 回答
0

您在下面使用了 DbAdpter Class.my 代码：

public class DBAdpter {
    public static String url = YourServerlink;

    public static String loginInUser(String username, String password) {
        String result = "";
        String msg = "";
        InputStream is = null;

        ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
        nameValuePairs.add(new BasicNameValuePair("username", username));
        nameValuePairs.add(new BasicNameValuePair("password", password));

        try {
            DefaultHttpClient httpclient = new DefaultHttpClient();

            HttpPost httppost = new HttpPost(url + "login.php?");
            httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
            HttpResponse response = httpclient.execute(httppost);
            HttpEntity entity = response.getEntity();
            is = entity.getContent();
        } catch (Exception e) {
            Log.e("log_tag", "Error in http connection " + e.toString());
        }
        // convert response to string
        try {
            BufferedReader reader = new BufferedReader(new InputStreamReader(
                    is, "iso-8859-1"), 8);
            StringBuilder sb = new StringBuilder();
            String line = null;
            while ((line = reader.readLine()) != null) {
                sb.append(line + "\n");
            }
            is.close();
            result = sb.toString().trim();

        } catch (Exception e) {
            Log.e("log_tag", "Error converting result " + e.toString());
        }

        try {
            JSONObject jObj = new JSONObject(result);
            msg = jObj.getString("Message");
        } catch (JSONException e) {
            e.printStackTrace();
        }
        return msg;
    }

您使用登录页面将我的代码放在下面的创建方法上：

            uname = (EditText) findViewById(R.id.user_edt_lg);
        pass = (EditText) findViewById(R.id.pass_edt_lg);
        login = (Button) findViewById(R.id.login);
        reg_txt = (TextView) findViewById(R.id.reg_txt);
        login.setOnClickListener(new View.OnClickListener() {

            public void onClick(View v) {
                strUname = uname.getText().toString().trim();
                strPass = pass.getText().toString().trim();
                DBAdpter.loginInUser(strUname, strPass);
                Toast.makeText(QuizActivity.this, "Successfully login", 1)
                        .show();

                Intent i = new Intent(QuizActivity.this, All_Quiz_list.class);
                startActivity(i);

            }
        });
于 2012-11-01T09:49:47.000 回答
0

这是用户从 Web 服务器登录的好例子。

1.安卓登录应用

于 2012-11-01T09:50:33.467 回答