php - 从 2 个不同的表中选择行

Question

有这样的桌子

Table "checklist"
idCardno
name
permAddress
datetime

Table "persons"
name
idcardno
photo

现在我想要我的 sqlquery

idCardno    |  name    | permAddress   | photo   
-----------------------------------------------
A123456     | John Doe | 302 xyz       | 1.gif

照片应该是idcardno的对应照片。

我怎样才能达到这样的结果？我的 sql 查询会是什么？谢谢

Answer 1

select checklist.idCardno as idCardno, checklist.name as name, permAddress, photo
from checklist, persons 
where checklist.idCardno = persons.idCardno

Answer 2

您可以使用 JOIN

SELECT checklist.idCardno, checklist.name, permAddress, photo 
FROM checklist JOIN persons 
ON checklist.idCardno = persons.idcardno

Answer 3

SELECT
   C.IDCARDNo
 , C.name
 , C.permAddress
 , P.Photo
FROM checklist C 
INNER JOIN persons P ON C.Idcardno = P.idCardno

Answer 4

你需要使用JOIN

select  C.idCardno,
        C.name,
        C.permAddress,
        P.photo   
from checklist C
join persons P
on   C.idCardno=P.idCardno

Answer 5

如果idCardno <-> idcardno是两个表之间的共享键，并且您想要输出的名称是来自人员的名称，则只需使用 JOIN：

SELECT c.idCardno, p.name, permAddress, photo FROM checklist c JOIN persons p ON c.idCardno = p.idcardno

Answer 6

从清单中选择 c.idCardno, c.name,c.permAddress,p.photo 作为 c 离开人员作为 p on c.idCardno=p.idCardno

Answer 7

使用加入：

select 
C.idCardno,C.name,C.permAddress,P.photo   
from checklist C
join persons P
on C.idCardno=P.idCardno

参考链接参考：加入