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我正在尝试聚合一些 youtube 提要，将它们连接起来，然后解析提要。当我自己解析单个提要时，我没有任何问题，而且代码似乎可以工作。但是，当我尝试将提要聚合为一个长字符串然后使用 etree.fromstring(aggregate_partner_feed) 时，出现错误。我得到的错误是 ParseError: unbound prefix 和 etree 行（前面引用过）作为错误给出。关于如何解决这个问题的任何建议？

aggregated_partners_list = [cnn, teamcoco, buzzfeed]


i = 1 
number_of_partners = len(aggregated_partners_list)
aggregate_partner_feed = '' 

for entry in aggregated_partners_list:
    #YOUTUBE FEED
    #download the file:
    file = urllib2.urlopen('http://gdata.youtube.com/feeds/api/users/'+entry+'/uploads?v=2&max-results=50')
    #convert to string:
    data = file.read()
    #close file because we dont need it anymore:
    file.close()

    if i == 1:
        #remove ending </feed>
        data = data[:-7]

    if i>1 and i != number_of_partners:
        data = data[data.find('<entry'):]
        data = data[:-7]
        #remove everything before first <entry> in the new feed and the last </entry>

    #if last, then only remove everything before first <entry>
    if i == number_of_partners:
        data = data[data.find('<entry'):]

    #append the current feed to the existing feed
    aggregate_partner_feed += data

    #increment the counter  
    i=i+1

print isinstance(data, basestring)                      #returns true
print isinstance(aggregate_partner_feed, basestring)    #returns true

#apply the parsing to the aggregated feed

#entire feed
root = etree.fromstring(aggregate_partner_feed)     #this is the line that give an error
#all entries
entries = root.findall('{http://www.w3.org/2005/Atom}entry')
#more code that seems to work...
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1 回答 1

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我单独解析每个提要，然后使用 .append 而不是将字符串连接在一起然后解析。

于 2012-11-01T05:03:32.227 回答