早在五月份，我就发布了这个问题。我试图在不同的应用程序上再次做同样的事情，但我还没有找到解决这个问题的方法。我确实有更多的信息和更好的代码，所以我希望你们能帮助我解决这个问题。
用例：医生办公室有一个包含管理员用户的网站。User用户通过模型和.CakePHP 的 Auth 成功登录UsersController。
医生有完全不同的个人资料和行动的转诊医生。医生需要通过 登录example.com/physicians/login。但是，此登录失败
authError => 'You are not authorized to access that location.'
这是我的代码AppController：
class AppController extends Controller {
public $helpers = array('Form', 'Html', 'Time', 'Session', 'Js' => array('Jquery'));
public $components = array(
'Session',
'Auth' => array(
'autoRedirect' => false,
'authorize' => 'Controller'
)
);
public function beforeFilter() {
$this->Auth->allow('index', 'view', 'edit', 'display', 'featured', 'events', 'contact', 'signup', 'search', 'view_category', 'view_archive', 'addComment', 'schedule', 'login');
}
}
这是我UsersController的工作：
class UsersController extends AppController {
public $components = array(
'Auth' => array(
'authenticate' => array(
'Form' => array(
'userModel' => 'User',
'fields' => array(
'username' => 'username',
'password' => 'password'
)
)
),
'loginRedirect' => array('controller' => 'users', 'action' => 'admin'),
'logoutRedirect' => array('controller' => 'pages', 'action' => 'index'),
'loginAction' => array('controller' => 'users', 'action' => 'login'),
'sessionKey' => 'Admin'
)
);
public function beforeFilter() {
parent::beforeFilter();
$this->Auth->allow('add', 'login', 'logout');
}
function isAuthorized() {
return true;
}
public function login() {
if ($this->request->is('post')) {
if ($this->Auth->login()) {
$this->redirect($this->Auth->redirect());
} else {
$this->Session->setFlash(__('Invalid username or password, try again'));
}
}
}
public function logout() {
$this->Session->destroy();
$this->redirect($this->Auth->logout());
}
这是我的PhysiciansController代码不起作用：
class PhysiciansController extends AppController {
public $components = array(
'Auth' => array(
'authenticate' => array(
'Form' => array(
'userModel' => 'Physician',
'fields' => array(
'username' => 'username',
'password' => 'password'
)
)
),
'loginRedirect' => array('controller' => 'physicians', 'action' => 'dashboard'),
'logoutRedirect' => array('controller' => 'pages', 'action' => 'index'),
'loginAction' => array('controller' => 'physicians', 'action' => 'login'),
'sessionKey' => 'Physician'
)
);
public function beforeFilter() {
parent::beforeFilter();
$this->Auth->authorize = array(
'Actions' => array(
'userModel' => 'Physician',
'actionPath' => 'physicians'
)
);
$this->Auth->allow('login', 'logout');
// $this->Session->write('Auth.redirect','/physicians/index');
}
function isAuthorized() {
return true;
}
public function login() {
if ($this->request->is('post')) {
if ($this->Auth->login()) {
$this->redirect(array('controller' => 'physicians', 'action' => 'dashboard'));
} else {
$this->Session->read();
debug($this->Auth);
$this->Session->setFlash(__('Invalid username or password, try again'));
}
}
}
public function logout() {
$this->Session->destroy();
$this->redirect($this->Auth->logout());
}
我真的不想重新开始并切换到 ACL —— 我不确定这对于两次登录是否是必要的。非常感谢您的帮助！
编辑：Joshua 在下面的回答很棒而且非常有帮助。我实现了它，但是当我尝试通过/phys/physican/login（前缀/控制器/操作）以医师身份登录时，我仍然收到未经授权的错误。管理员设置效果很好。这是我尝试登录时的调试代码：
object(AuthComponent) {
components => array(
(int) 0 => 'Session',
(int) 1 => 'RequestHandler'
)
authenticate => array(
'Form' => array(
'userModel' => 'Physician'
)
)
authorize => false
ajaxLogin => null
flash => array(
'element' => 'default',
'key' => 'auth',
'params' => array()
)
loginAction => array(
'controller' => 'physicians',
'action' => 'phys_login'
)
loginRedirect => null
logoutRedirect => '/'
authError => 'You are not authorized to access that location.'
allowedActions => array()
request => object(CakeRequest) {
params => array(
'prefix' => '*****',
'plugin' => null,
'controller' => 'physicians',
'action' => 'phys_login',
'named' => array(),
'pass' => array(),
'phys' => true,
'_Token' => array(
'key' => 'ad1ea69c3b2c7b9e833bbda03ef18b04079b23c3',
'unlockedFields' => array()
),
'isAjax' => false
)
data => array(
'Physician' => array(
'password' => '*****',
'username' => 'deewilcox'
)
)
query => array()
url => 'phys/physicians/login'
base => ''
webroot => '/'
here => '/phys/physicians/login'
}
response => object(CakeResponse) {
}
settings => array()
}