输入数字金额后，我需要自动获取文字金额。
eg：如果我输入2500，它应该在下一个字段中自动插入为2500。
是否可以在 sql server 中提供解释。谢谢。
问问题
4003 次
2 回答
1
Please use the below function to Convert into the word:
CREATE FUNCTION [dbo].[Currency_ToWords] (
@Input Numeric (38) -- Input number with as many as 18 digits
) RETURNS VARCHAR(8000)
/*
* Converts a integer number as large as 34 digits into the
* equivalent words. The first letter is capitalized.
*
* Attribution: Based on NumberToWords by Srinivas Sampath
* as revised by Nick Barclay
*
* Example:
select dbo.udf_Num_ToWords (1234567890) + CHAR(10)
+ dbo.udf_Num_ToWords (0) + CHAR(10)
+ dbo.udf_Num_ToWords (123) + CHAR(10)
select dbo.udf_Num_ToWords(76543210987654321098765432109876543210)
DECLARE @i numeric (38,0)
SET @i = 0
WHILE @I <= 1000 BEGIN
PRINT convert (char(5), @i)
+ convert(varchar(255), dbo.udf_Num_ToWords(@i))
SET @I = @i + 1
END
*
* Published as the T-SQL UDF of the Week Vol 2 #9 2/17/03
****************************************************************/
AS BEGIN
Declare @Number Numeric(38,0)
set @Number = @Input
Declare @Cents as int
set @Cents = 100*Convert(money,(@Input - convert(Numeric(38,3),@Number)))
DECLARE @inputNumber VARCHAR(38)
DECLARE @NumbersTable TABLE (number CHAR(2), word VARCHAR(10))
DECLARE @outputString VARCHAR(8000)
DECLARE @length INT
DECLARE @counter INT
DECLARE @loops INT
DECLARE @position INT
DECLARE @chunk CHAR(3) -- for chunks of 3 numbers
DECLARE @tensones CHAR(2)
DECLARE @hundreds CHAR(1)
DECLARE @tens CHAR(1)
DECLARE @ones CHAR(1)
IF @Number = 0 Return 'Zero'
-- initialize the variables
SELECT @inputNumber = CONVERT(varchar(38), @Number)
, @outputString = ''
, @counter = 1
SELECT @length = LEN(@inputNumber)
, @position = LEN(@inputNumber) - 2
, @loops = LEN(@inputNumber)/3
-- make sure there is an extra loop added for the remaining numbers
IF LEN(@inputNumber) % 3 <> 0 SET @loops = @loops + 1
-- insert data for the numbers and words
INSERT INTO @NumbersTable SELECT '00', ''
UNION ALL SELECT '01', 'one' UNION ALL SELECT '02', 'two'
UNION ALL SELECT '03', 'three' UNION ALL SELECT '04', 'four'
UNION ALL SELECT '05', 'five' UNION ALL SELECT '06', 'six'
UNION ALL SELECT '07', 'seven' UNION ALL SELECT '08', 'eight'
UNION ALL SELECT '09', 'nine' UNION ALL SELECT '10', 'ten'
UNION ALL SELECT '11', 'eleven' UNION ALL SELECT '12', 'twelve'
UNION ALL SELECT '13', 'thirteen' UNION ALL SELECT '14', 'fourteen'
UNION ALL SELECT '15', 'fifteen' UNION ALL SELECT '16', 'sixteen'
UNION ALL SELECT '17', 'seventeen' UNION ALL SELECT '18', 'eighteen'
UNION ALL SELECT '19', 'nineteen' UNION ALL SELECT '20', 'twenty'
UNION ALL SELECT '30', 'thirty' UNION ALL SELECT '40', 'forty'
UNION ALL SELECT '50', 'fifty' UNION ALL SELECT '60', 'sixty'
UNION ALL SELECT '70', 'seventy' UNION ALL SELECT '80', 'eighty'
UNION ALL SELECT '90', 'ninety'
WHILE @counter <= @loops BEGIN
-- get chunks of 3 numbers at a time, padded with leading zeros
SET @chunk = RIGHT('000' + SUBSTRING(@inputNumber, @position, 3), 3)
IF @chunk <> '000' BEGIN
SELECT @tensones = SUBSTRING(@chunk, 2, 2)
, @hundreds = SUBSTRING(@chunk, 1, 1)
, @tens = SUBSTRING(@chunk, 2, 1)
, @ones = SUBSTRING(@chunk, 3, 1)
-- If twenty or less, use the word directly from @NumbersTable
IF CONVERT(INT, @tensones) <= 20 OR @Ones='0' BEGIN
SET @outputString = (SELECT word
FROM @NumbersTable
WHERE @tensones = number)
+ CASE @counter WHEN 1 THEN '' -- No name
WHEN 2 THEN ' thousand ' WHEN 3 THEN ' million '
WHEN 4 THEN ' billion ' WHEN 5 THEN ' trillion '
WHEN 6 THEN ' quadrillion ' WHEN 7 THEN ' quintillion '
WHEN 8 THEN ' sextillion ' WHEN 9 THEN ' septillion '
WHEN 10 THEN ' octillion ' WHEN 11 THEN ' nonillion '
WHEN 12 THEN ' decillion ' WHEN 13 THEN ' undecillion '
ELSE '' END
+ @outputString
END
ELSE BEGIN -- break down the ones and the tens separately
SET @outputString = ' '
+ (SELECT word
FROM @NumbersTable
WHERE @tens + '0' = number)
+ '-'
+ (SELECT word
FROM @NumbersTable
WHERE '0'+ @ones = number)
+ CASE @counter WHEN 1 THEN '' -- No name
WHEN 2 THEN ' thousand ' WHEN 3 THEN ' million '
WHEN 4 THEN ' billion ' WHEN 5 THEN ' trillion '
WHEN 6 THEN ' quadrillion ' WHEN 7 THEN ' quintillion '
WHEN 8 THEN ' sextillion ' WHEN 9 THEN ' septillion '
WHEN 10 THEN ' octillion ' WHEN 11 THEN ' nonillion '
WHEN 12 THEN ' decillion ' WHEN 13 THEN ' undecillion '
ELSE '' END
+ @outputString
END
-- now get the hundreds
IF @hundreds <> '0' BEGIN
SET @outputString = (SELECT word
FROM @NumbersTable
WHERE '0' + @hundreds = number)
+ ' hundred '
+ @outputString
END
END
SELECT @counter = @counter + 1
, @position = @position - 3
END
-- Remove any double spaces
SET @outputString = LTRIM(RTRIM(REPLACE(@outputString, ' ', ' ')))
SET @outputstring = UPPER(LEFT(@outputstring, 1)) + SUBSTRING(@outputstring, 2, 8000)
RETURN UPPER(@outputString) -- return the result
END
For E.x : SELECT dbo.Currency_ToWords(2500)
OUTPUT: TWO THOUSAND FIVE HUNDRED
于 2012-10-31T08:19:09.730 回答
0
我想说最好的解决方案是创建一个函数来实现将数字转换为单词的逻辑。网上有这种逻辑的例子，例如：http ://www.meadinkent.co.uk/xlnumberstext.htm它只需要转换为t-sql。
然后存储数值并使用计算字段导出字符串值。计算字段将调用您的新函数并传入数字列，结果将是数字的字符串表示形式。
有关计算字段的参考，请查看此处：http: //msdn.microsoft.com/en-us/library/ms191250 (v=sql.105).aspx
有关创建函数的参考，请查看此处：http: //msdn.microsoft.com/en-us/library/ms186755.aspx
于 2012-10-31T07:19:48.520 回答