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在我的基于 gevent 的程序中,我在某个地方有一个线程,它陷入了一个循环,例如:

while True:
    gevent.sleep(0)

我怎样才能弄清楚这是哪个线程?是否可以列出(并获取堆栈跟踪)正在运行的线程?

4

2 回答 2

1

方法1.超时

我在我的代码中使用它来跟踪可能阻塞的greenlets。发生这种情况时会引发 NodeTaskTimeout。只需将您的作业包装在 Timeout 中或为它们提供 TimeOut 对象。

 with Timeout(90, False):
        task_jobs.join()
    
    if task_jobs:
        print 'task jobs killed', task_jobs
        task_jobs.kill()
        if settings.DEBUG:
            raise NodeTaskTimeout

如果它挂起/阻塞/花费很长时间,这个打印就完成了任务。特别令人讨厌的是那些相互依赖并导致死锁 job1 /thread -> job2/thread2 -> job3/thread3 和 job/thread3 只有在 job1 完成时才会完成,这永远不会发生,因为 job2 没有完成而 job2 没有因为job3没有完成而完成..你明白了;)

方法 2 Settrace

http://www.rfk.id.au/blog/entry/detect-gevent-blocking-with-greenlet-settrace/

但是您还需要将您怀疑“旋转”的代码放入 with 块中。

于 2014-09-04T09:47:56.130 回答
0

有一个用于检查块的官方 API,它会查明导致块的确切行,检查代码示例如下:

# gevent        1.3.7
# greenlet      0.4.15
# zope.event    4.4
import gevent
from gevent import config, get_hub
from gevent.events import IEventLoopBlocked
import logging
from pprint import pformat
import time
import zope.event

# initial logging
logging.basicConfig(level=logging.INFO)
log = logging.getLogger(__name__)

# setup gevent config
# enable the monitor thread
config.monitor_thread = True
config.max_blocking_time = 4

# start the monitor thread
hub = get_hub()
monitor = hub.start_periodic_monitoring_thread()

# register the event to logging system
def g(event):
    log.error('Greenlet: {}, exceed the max blocking time: {}'.format(event.greenlet, event.blocking_time))
    log.error(pformat(event.info))
event = IEventLoopBlocked()
zope.event.subscribers.append(g)

# you can also create you own monitoring function
# def check(hub):
#     print('< periodic check in monitoring thread >')
#
# monitor.add_monitoring_function(check, 1)

def gl1():
    # use time.sleep to trigger block
    log.info('block at gl1 for 2 seconds')
    time.sleep(2)
    log.info('leave gl1 now')

def gl2():
    # use time.sleep to trigger block
    log.info('block at gl2 for 6 seconds should be detected')
    time.sleep(6)
    log.info('leave gl2 now')

def gl3():
    # gevent.sleep will not block
    log.info('gl3 will not block since it use gevent.sleep')
    gevent.sleep(8)
    log.info('leave gl3 now')


gevent.joinall([
    gevent.spawn(gl3),
    gevent.spawn(gl1),
    gevent.spawn(gl2),
])

我希望它有帮助!

于 2020-03-08T09:02:41.800 回答