22

我要做的是我必须在给定的 URL 中发布 JSON 数据我的 JSON 看起来像

{
    "trip_title":"My Hotel Booking",
    "traveler_info":{
        "first_name":"Edward",
        "middle_name":"",
        "last_name":"Cullen",
        "phone":{
            "country_code":"1",
            "area_code":"425",
            "number":"6795089"
        },
        "email":"asdv@gmail.com"
    },
    "billing_info":{
        "credit_card":{
            "card_number":"47135821",
            "card_type":"Visa",
            "card_security_code":"123",
            "expiration_month":"09",
            "expiration_year":"2017"
        },
        "first_name":"Edward",
        "last_name":"Cullen",
        "billing_address":{
            "street1":"Expedia Inc",
            "street2":"108th Ave NE",
            "suite":"333",
            "city":"Bellevue",
            "state":"WA",
            "country":"USA",
            "zipcode":"98004"
        },
        "phone":{
            "country_code":"1",
            "area_code":"425",
            "number":"782"
        }
    },
    "marketing_code":""
}

我的功能

string message = "URL";
_body="JSON DATA";
HttpWebRequest request = HttpWebRequest.Create(message) as HttpWebRequest;
if (!string.IsNullOrEmpty(_body))
{
    request.ContentType =  "text/json";
    request.Method =  "POST";

    using (var streamWriter = new StreamWriter(request.GetRequestStream()))
    {
        streamWriter.Write(_body);
        streamWriter.Flush();
        streamWriter.Close();
    }
}

using (HttpWebResponse webresponse = request.GetResponse() as HttpWebResponse)
{
    using (StreamReader reader = new StreamReader(webresponse.GetResponseStream()))
    {
        string response = reader.ReadToEnd();
    }
}

当我发布它时；我收到一个错误

“远程服务器返回错误：（415）不支持的媒体类型。”

任何人都对此有想法；我在哪里弄错了？

4

7 回答 7

28

尝试这个：

request.ContentType =  "application/json"
于 2012-10-30T13:44:28.493 回答
7

对于 WebAPI >> 如果您是calling this POST method from fiddler，只需在标题中添加以下行。

Content-Type: application/json
于 2018-02-06T07:18:12.957 回答
2

正如其他人所回答的那样，问题出在 ContentType 上。应该是“应用程序/json”。

这是旧 WebRequest 的示例

var parameters = Newtonsoft.Json.JsonConvert.SerializeObject(obj);

var req = WebRequest.Create(uri);

req.Method = "POST";
req.ContentType = "application/json";

byte[] bytes = Encoding.ASCII.GetBytes(parameters);

req.ContentLength = bytes.Length;

using (var os = req.GetRequestStream())
{
    os.Write(bytes, 0, bytes.Length);

    os.Close();
}

var stream = req.GetResponse().GetResponseStream();

if (stream != null)
    using (stream)
    using (var sr = new StreamReader(stream))
    {
        return sr.ReadToEnd().Trim();
    }
return "Response was null";
于 2016-04-12T03:01:27.683 回答
1

I renamed my project and updated all of the namespaces to correlate after which I got this exact same message. I realized that I had not updated the namespaces in the web.config (name and contract):

<system.serviceModel>
  <services>
    <service name="X.Y.Z.Authentication" behaviorConfiguration="ServiceBehaviour">
      <endpoint address="" binding="webHttpBinding" contract="X.Y.Z.IAuthentication" behaviorConfiguration="web" bindingConfiguration="defaultRestJsonp"></endpoint>
    </service>
  </...>
</..>

Hope this helps anyone reading this.

于 2014-01-06T13:40:06.513 回答
0

我不是 100% 确定，但我猜你必须将文本作为 byteArray 发送，试试这个：

req = (HttpWebRequest)HttpWebRequest.Create(uri);
        req.CookieContainer = cookieContainer;
        req.Method = "POST";
        req.ContentType = "text/json";
        byte[] byteArray2 = Encoding.ASCII.GetBytes(body);
        req.ContentLength = byteArray2.Length;
        Stream newStream = req.GetRequestStream();
        newStream.Write(byteArray2, 0, byteArray2.Length);
        newStream.Close();
于 2012-10-30T13:50:05.627 回答
0

这是我为接受 json 数据的 web api 函数创建的代码示例

string Serialized = JsonConvert.SerializeObject(jsonData);
using (var client = new HttpClient())
{
    client.DefaultRequestHeaders.Accept.Clear();
    client.DefaultRequestHeaders.Accept.Add(new MediaTypeWithQualityHeaderValue("application/json"));
    HttpContent content = new StringContent(Serialized, Encoding.Unicode, "application/json"); 
    var response = await client.PostAsync("http://localhost:1234", content);   
}
于 2015-02-05T11:04:31.917 回答
0

序列化您要传递的数据并对其进行编码。另外，提到 req.ContentType = "application/json";

“马丁”代码有效。

LoginInfo obj = new LoginInfo();

obj.username = uname;
obj.password = pwd;
var parameters = Newtonsoft.Json.JsonConvert.SerializeObject(obj);

var req = WebRequest.Create(uri);

req.Method = "POST";
req.ContentType = "application/json";

byte[] bytes = Encoding.ASCII.GetBytes(parameters);

req.ContentLength = bytes.Length;

using (var os = req.GetRequestStream())
{
    os.Write(bytes, 0, bytes.Length);

    os.Close();
}

var stream = req.GetResponse().GetResponseStream();

if (stream != null)
    using (stream)
    using (var sr = new StreamReader(stream))
    {
        return sr.ReadToEnd().Trim();
    }
于 2016-10-26T09:35:21.310 回答