0

我需要创建一个查询以基于日期间隔返回 N 行。这很简单，但我不能：/

基本查询：

SELECT
  f.many_fields
FROM
  tb_foo f
WHERE
  f.id_foo = 14

此查询根据我的 ID 返回 1 行。但是，我在“2012-10-30”处设置了“2012-10-10”之类的日期间隔来应用于此查询，最后基本查询将根据日期间隔的差异返回 20 行。

可以做到这一点吗？

SELECT
  f.many_fields,
  bar.*
FROM
  tb_foo f,
  (SELECT x FROM dual limit DATEDIFF('2012-10-10','2012-10-30')) bar
WHERE
  f.id_foo = 14

真实查询：

SELECT
  m.id_matricula,
  a.nome
FROM
  tb_matricula m
    inner join tb_aluno a on (a.id_aluno = m.id_matricula)
WHERE
  m.id_matricula = 14

开始日期 = 2012-10-10 结束日期 = 2012-10-30

我将在 iReport 上使用此结果，根据此日期之间的差异构建一个包含行数的网格。

基于 Google 搜索的示例：

SELECT
    CONCAT( dt.d ,'-' ,days.d ) AS dates
FROM
    (
        SELECT
            CONCAT( a1 ,b1 ) AS d
        FROM
            (
                SELECT
                    '0' AS a1
            UNION ALL SELECT
                    '1'
            UNION ALL SELECT
                    '2'
            UNION ALL SELECT
                    '3'
            ) a JOIN(
                SELECT
                    '0' AS b1
            UNION ALL SELECT
                    '1'
            UNION ALL SELECT
                    '2'
            UNION ALL SELECT
                    '3'
            UNION ALL SELECT
                    '4'
            UNION ALL SELECT
                    '5'
            UNION ALL SELECT
                    '6'
            UNION ALL SELECT
                    '7'
            UNION ALL SELECT
                    '8'
            UNION ALL SELECT
                    '9'
            ) b
        WHERE
            CONVERT(
                CONCAT( a1 ,b1 ) ,
                UNSIGNED
            ) <=(
                SELECT
                    DAY(
                        CONCAT( '2012-10' ,'-01' ) + INTERVAL 1 MONTH - INTERVAL 1 DAY
                    )
            )
            AND CONCAT( a1 ,b1 ) <> '00'
    ) days JOIN(
        SELECT
            '2012-10' AS d
    ) dt
 HAVING
    dates BETWEEN '2012-10-02' AND '2012-10-05'
ORDER BY
    dates
;
4

1 回答 1

0

我找到了解决方案。使用子查询我可以根据日期间隔返回许多行，这与主查询没有任何关系。所以我有这个：

SELECT
    datas. * ,
    m.id_matricula ,
    p.nome
FROM
    tb_matricula m INNER JOIN tb_aluno a
        ON(
        a.id_aluno = m.id_aluno
    ) INNER JOIN tb_perfil p
        ON(
        p.id_perfil = a.id_perfil
    ) ,
    (
        SELECT
            CONCAT( dt.d ,'-' ,days.d ) AS dates
        FROM
            (
                SELECT
                    CONCAT( a1 ,b1 ) AS d
                FROM
                    (
                        SELECT
                            '0' AS a1
                    UNION ALL SELECT
                            '1'
                    UNION ALL SELECT
                            '2'
                    UNION ALL SELECT
                            '3'
                    ) a JOIN(
                        SELECT
                            '0' AS b1
                    UNION ALL SELECT
                            '1'
                    UNION ALL SELECT
                            '2'
                    UNION ALL SELECT
                            '3'
                    UNION ALL SELECT
                            '4'
                    UNION ALL SELECT
                            '5'
                    UNION ALL SELECT
                            '6'
                    UNION ALL SELECT
                            '7'
                    UNION ALL SELECT
                            '8'
                    UNION ALL SELECT
                            '9'
                    ) b
                WHERE
                    CONVERT(
                        CONCAT( a1 ,b1 ) ,
                        UNSIGNED
                    ) <=(
                        SELECT
                            DAY(
                                CONCAT( '2012-02' ,'-01' ) + INTERVAL 1 MONTH - INTERVAL 1 DAY
                            )
                    )
                    AND CONCAT( a1 ,b1 ) <> '00'
            ) days JOIN(
                SELECT
                    '2012-02' AS d
            ) dt
    UNION ALL SELECT
            CONCAT( dt.d ,'-' ,days.d ) AS dates
        FROM
            (
                SELECT
                    CONCAT( a1 ,b1 ) AS d
                FROM
                    (
                        SELECT
                            '0' AS a1
                    UNION ALL SELECT
                            '1'
                    UNION ALL SELECT
                            '2'
                    UNION ALL SELECT
                            '3'
                    ) a JOIN(
                        SELECT
                            '0' AS b1
                    UNION ALL SELECT
                            '1'
                    UNION ALL SELECT
                            '2'
                    UNION ALL SELECT
                            '3'
                    UNION ALL SELECT
                            '4'
                    UNION ALL SELECT
                            '5'
                    UNION ALL SELECT
                            '6'
                    UNION ALL SELECT
                            '7'
                    UNION ALL SELECT
                            '8'
                    UNION ALL SELECT
                            '9'
                    ) b
                WHERE
                    CONVERT(
                        CONCAT( a1 ,b1 ) ,
                        UNSIGNED
                    ) <=(
                        SELECT
                            DAY(
                                CONCAT( '2012-03' ,'-01' ) + INTERVAL 1 MONTH - INTERVAL 1 DAY
                            )
                    )
                    AND CONCAT( a1 ,b1 ) <> '00'
            ) days JOIN(
                SELECT
                    '2012-03' AS d
            ) dt
        ORDER BY
            dates
    ) datas
WHERE
    m.id_matricula = 42
    and
    datas.dates BETWEEN '2012-02-25' AND '2012-03-05';

为 ID = 42 和 3 天的日期差异运行此语句，我有：

DATES,          ID_MATRICULA, NOME
2012-02-25  42        R ANDRE F DOMINGOS
2012-02-26  42        R ANDRE F DOMINGOS
2012-02-27  42        R ANDRE F DOMINGOS
于 2012-10-30T15:28:55.500 回答