6 
         try 
         {

            url= new URL(ConstantsClass.VENDOR_FOLLOW + "?UID=" +android_id+"&URL='"+resultfinal+"'&device=android");


                connection = (HttpURLConnection) url.openConnection();
                connection.setDoOutput(true);
                connection.setRequestMethod("POST");

                request = new OutputStreamWriter(connection.getOutputStream());
                request.flush();
                request.close();
                request.write("Hello!!!");

                String line = "";
                InputStreamReader isr = new InputStreamReader(connection.getInputStream());
                BufferedReader reader = new BufferedReader(isr);

                StringBuffer sb = new StringBuffer();

                while((line=reader.readLine())!=null) {
                    sb.append(line + "&");
                }

                response = sb.toString();
                //response.getEntity().getContent();

                Log.i("Test", "updated response: " + response);



            }
         catch (IOException e) {
              e.printStackTrace();
          }

            Log.i("Test", "**************url list********************" + url);
         tag_text.setOnClickListener(new OnClickListener() {
                public void onClick(View v) {
                    // TODO Auto-generated method stub
                    Intent in=new Intent(context,LinkWebView.class);
                    in.putExtra("vendorUrl", resultfinal);
                    context.startActivity(in);      
                    //postData();
                }
            });
             }

    tag_text.setTextSize(16);
    return view;

}

嗨，我是 android 新手，我正在尝试将值从 url 传递到服务器，但我在服务器端传递了空值。更新响应为空。我的服务器端值没有给我任何值。我需要从上面给出的 url 传递 url、android_id 和设备。我也尝试了httpclient，但它也给了我空值。

4

2 回答 2

12

你应该试试下面的代码，它对我来说运行得很好。

   // ADD YOUR REQUEST DATA HERE  (you can pass number of variable).
    ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
    nameValuePairs.add(new BasicNameValuePair("Your_var_1", value));
    nameValuePairs.add(new BasicNameValuePair("Your_var_2", value));

现在建立您的网络连接，例如

(1) 向服务器发送简单字符串

    try
    {
        HttpClient httpclient = new DefaultHttpClient();
        HttpPost httppost = new HttpPost("your url only ex:www.google.com/abc");
        httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
        HttpParams httpParameters = new BasicHttpParams();
        DefaultHttpClient httpClient = new DefaultHttpClient(httpParameters);
        HttpResponse response = httpclient.execute(httppost);
        HttpEntity entity = response.getEntity();
        is = entity.getContent();
    } catch (Exception e) 
    {   
        Log.e("Loading Runnable Error in http connection  :", e.toString());
    }

(2) 向服务器发送 JSON Encode 字符串

HttpClient client = new DefaultHttpClient();
HttpConnectionParams.setConnectionTimeout(client.getParams(), 10000); //Timeout Limit
HttpResponse response;
JSONObject json = new JSONObject();

try {
HttpPost post = new HttpPost(URL);
json.put("user_name", "chintan");
json.put("password", "khetiya");
StringEntity se = new StringEntity( json.toString());  
se.setContentType(new BasicHeader(HTTP.CONTENT_TYPE, "application/json"));
post.setEntity(se);
response = client.execute(post);

 /*Checking response */
if(response!=null){
is = response.getEntity().getContent(); //Get the data in the entity
 }

} catch(Exception e) {
e.printStackTrace();
createDialog("Error", "Cannot Estabilish Connection");
}

两种情况下的响应都相同

try 
    {
        BufferedReader reader = new BufferedReader(new InputStreamReader(is, "iso-8859-1"), 8);
        StringBuilder sb = new StringBuilder();
        String line = null;
        while ((line = reader.readLine()) != null) 
        {
            sb.append(line + "\n");
        }
        is.close();
        result = sb.toString();
    }
    catch (Exception e) 
    {   
        Log.e("Loading Runnable Error converting result :", e.toString());
    }

现在最终结果包含整个输出字符串，这取决于您将如何读取数据。使用 json 或其他。我正在使用 json 所以放它的示例代码可能对你有帮助。

JSONObject json_data = new JSONObject(result);// its a string var which contain output. 
        my_output_one = json_data.getString("var_1"); // its your response var form web.
        my_output_two = json_data.getString("var_2");

现在它结束了，您有两个变量，它们具有任何类型的值并使用任何类型。

现在这将对您有所帮助。如果您有任何疑问，请告诉我。

于 2012-10-30T07:13:30.197 回答
1

请在写入后调用刷新并在 finally 块中关闭流。查看以下代码：

   try 
         {

            url= new URL(ConstantsClass.VENDOR_FOLLOW + "?UID=" +android_id+"&URL='"+resultfinal+"'&device=android");


                connection = (HttpURLConnection) url.openConnection();
                connection.setDoOutput(true);
                connection.setRequestMethod("POST");

                request = new OutputStreamWriter(connection.getOutputStream());
                request.write("Hello!!!");

                request.flush();


                String line = "";
                InputStreamReader isr = new InputStreamReader(connection.getInputStream());
                BufferedReader reader = new BufferedReader(isr);

                StringBuffer sb = new StringBuffer();

                while((line=reader.readLine())!=null) {
                    sb.append(line + "&");
                }

                response = sb.toString();
                //response.getEntity().getContent();

                Log.i("Test", "updated response: " + response);



            }
         catch (IOException e) {
              e.printStackTrace();
          }

            Log.i("Test", "**************url list********************" + url);
         tag_text.setOnClickListener(new OnClickListener() {
                public void onClick(View v) {
                    // TODO Auto-generated method stub
                    Intent in=new Intent(context,LinkWebView.class);
                    in.putExtra("vendorUrl", resultfinal);
                    context.startActivity(in);      
                    //postData();
                }
            });
             }

    tag_text.setTextSize(16);
    return view;

}finally{
              try{
                request.close();
              }catch(Exception e){}
 }
于 2012-10-30T06:57:20.320 回答