14

我有一个接口:IFoo
两个实现该接口的类:FooOneFooTwo
两个类ClassOne并在构造函数中ClassTwo接收一个IFoo参数。

我如何配置统一以便ClassOne接收一个FooOne实例并仅使用一个容器ClassTwo接收一个?FooTwo

我不能在运行时这样做,所以它必须在配置文件中。

4

3 回答 3

18

查看Unity 文档

要获得更易读的配置文件,您应该为、 、 和IFoo定义FooOne类型FooTwo别名。然后你需要注册映射到你的实现。您需要为映射设置一个。对于您的消费者,您需要注册一个.ClassOneClassTwoIFoonameIFooInjectionConstructor

您的配置将如下所示:

<?xml version="1.0" encoding="utf-8" ?>
<configuration>
  <configSections>
    <section name="unity" type="Microsoft.Practices.Unity.Configuration.UnityConfigurationSection,
      Microsoft.Practices.Unity.Configuration"/>
  </configSections>
  <unity xmlns="http://schemas.microsoft.com/practices/2010/unity">
    <alias alias="IFoo" type="UnityConfigFile.IFoo, UnityConfigFile" />
    <alias alias="FooOne" type="UnityConfigFile.FooOne, UnityConfigFile" />
    <alias alias="FooTwo" type="UnityConfigFile.FooTwo, UnityConfigFile" />
    <alias alias="ClassOne" type="UnityConfigFile.ClassOne, UnityConfigFile" />
    <alias alias="ClassTwo" type="UnityConfigFile.ClassTwo, UnityConfigFile" />
    <container>
      <register type="IFoo" name="1" mapTo="FooOne" />
      <register type="IFoo" name="2" mapTo="FooTwo" />
      <register type="ClassOne" mapTo="ClassOne">
        <constructor>
          <param name="foo">
            <dependency type="IFoo" name="1" />
          </param>
        </constructor>
      </register>
      <register type="ClassTwo" mapTo="ClassTwo">
        <constructor>
          <param name="foo">
            <dependency type="IFoo" name="2" />
          </param>
        </constructor>
      </register>
    </container>
  </unity>
</configuration>

这是显示它如何工作的相应测试。

UnityConfigurationSection config =
  (UnityConfigurationSection) ConfigurationManager.GetSection("unity");
IUnityContainer container = new UnityContainer();
container.LoadConfiguration(config);
ClassTwo two = container.Resolve<ClassTwo>();
Assert.IsInstanceOfType(two.Foo, typeof(FooTwo));

更新

在运行时你可以这样做

IUnityContainer container = new UnityContainer();
container.RegisterType<IFoo, FooOne>("One");
container.RegisterType<IFoo, FooTwo>("Two");
container.RegisterType<ClassOne>(new InjectionConstructor(
  new ResolvedParameter<IFoo>("One")));
container.RegisterType<ClassTwo>(new InjectionConstructor(
  new ResolvedParameter<IFoo>("Two")));
于 2012-10-30T10:00:20.300 回答
5

您需要为他们提供注册名称才能执行此操作:

// Create an instance of a service you want to use. Alternatively, this
// may have been created by another process and passed to your application
LoggingService myLoggingService = new LoggingService();

// Register the existing object instance with the container
container.RegisterInstance<IMyService>("Logging", myLoggingService);

// Register a mapping for another service your application will use
container.RegisterType<IMyService, myDataService>("DataService");

// When required, retrieve an instance of these services
IMyService theDataService = container.Resolve<IMyService>("DataService");
IMyService theLoggingService = container.Resolve<IMyService>("Logging");

取自使用 Unity 解析类型的实例

于 2012-10-29T22:36:09.243 回答
0

我像这样在我的应用程序中设置

已安装 Nuget 包 Unity 版本 4.0.1

<package id="Unity" version="4.0.1" targetFramework="net452" />

在我的 App.config

<configSections>
     <section name="unity" type="Microsoft.Practices.Unity.Configuration.UnityConfigurationSection, Microsoft.Practices.Unity.Configuration" />
</configSections>

<unity>
    <container>
        <register type="MyApp.MainWindow, MyApp">
            <lifetime type="singleton" />
        </register>
        <register name="UnityResolver" type="MyApp.Core.Interface.IResolver, MyApp.Core.Interface" mapTo="Avelyn.Core.Container.UnityResolver, Avelyn.Core" />
        <register name="NinjectResolver" type="MyApp.Core.Interface.IResolver, MyApp.Core.Interface" mapTo="Avelyn.Core.Container.NinjectResolver, Avelyn.Core" />
    </container>
</unity>

在我的 App.xaml.cs 中

var _container = new UnityContainer();
_container.LoadConfiguration();

IResolver _unityResolver = _container.Resolve<IResolver>("UnityResolver");
IResolver _ninject  = _container.Resolve<IResolver>("NinjectResolver");
MainWindow _win = _container.Resolve<MainWindow>();
于 2017-11-14T16:29:53.257 回答