2

我有以下实体：

1- 地址

@Entity
@Table(name = "Address")
public class Address implements Serializable
{
    private static final long serialVersionUID = 1L;

    @EmbeddedId
    private AddressPK id = new AddressPK();

               @OneToOne(mappedBy = "address")
    private Insurance_Detail insuranceDetail;

}

2-地址PK

@Embeddable
public class AddressPK implements Serializable
{
    // default serial version id, required for serializable classes.
    private static final long serialVersionUID = 1L;

    @Column(unique = false, nullable = false, length = 45)
    private String customer_EmailAddress;

    @Column(unique = true, nullable = false)
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private int address_Id;

}

3-保险_详情 

@Entity
@Table(name = "Insurance_Detail")
public class Insurance_Detail implements Serializable
{
    private static final long serialVersionUID = 1L;

    @EmbeddedId
    private AddressPK id;

    @OneToOne
@JoinColumns({
        @JoinColumn(name = "customer_EmailAddress", referencedColumnName = "customer_EmailAddress", nullable = false, insertable = false, updatable = false),
        @JoinColumn(name = "address_Id", referencedColumnName = "address_Id", nullable = false, insertable = false, updatable = false) })



}

4- 持久化地址对象如下：

Address address= new Address(data1,data2);

address.getId().setCustomer_EmailAddress(
                    currentCustomer.getEmailAddress());

entityManager.persist(address);

5-坚持保险明细对象如下：

Insurance_Detail insuranceDetail = new Insurance_Detail(address.getId(), data3,data4);
entityManager.persist(insuranceDetail);

并且保存正确，没有问题。

问题：当尝试持久化Insurance_Detail对象时，在第一次插入保险时，它已成功持久化，但在第二次插入另一个保险时，我得到以下异常。

javax.servlet.ServletException: org.springframework.orm.jpa.JpaSystemException: org.hibernate.exception.ConstraintViolationException: Duplicate entry 'test@msn.com' for key 'customer_EmailAddress'; nested exception is javax.persistence.PersistenceException: org.hibernate.exception.ConstraintViolationException: Duplicate entry 'test@msn.com' for key 'customer_EmailAddress'
    javax.faces.webapp.FacesServlet.service(FacesServlet.java:606)
    org.primefaces.webapp.filter.FileUploadFilter.doFilter(FileUploadFilter.java:79)
    org.springframework.security.web.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:330)
    org.springframework.security.web.access.intercept.FilterSecurityInterceptor.invoke(FilterSecurityInterceptor.java:118)
    org.springframework.security.web.access.intercept.FilterSecurityInterceptor.doFilter(FilterSecurityInterceptor.java:84)
    org.springframework.security.web.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:342)
    org.springframework.security.web.access.ExceptionTranslationFilter.doFilter(ExceptionTranslationFilter.java:113)
    org.springframework.security.web.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:342)
    org.springframework.security.web.session.SessionManagementFilter.doFilter(SessionManagementFilter.java:103)
    org.springframework.security.web.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:342)
    org.springframework.security.web.authentication.AnonymousAuthenticationFilter.doFilter(AnonymousAuthenticationFilter.java:113)
    org.springframework.security.web.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:342)
    org.springframework.security.web.servletapi.SecurityContextHolderAwareRequestFilter.doFilter(SecurityContextHolderAwareRequestFilter.java:54)
    org.springframework.security.web.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:342)
    org.springframework.security.web.savedrequest.RequestCacheAwareFilter.doFilter(RequestCacheAwareFilter.java:45)
    org.springframework.security.web.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:342)
    org.springframework.security.web.authentication.www.BasicAuthenticationFilter.doFilter(BasicAuthenticationFilter.java:150)
    org.springframework.security.web.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:342)
    org.springframework.security.web.authentication.AbstractAuthenticationProcessingFilter.doFilter(AbstractAuthenticationProcessingFilter.java:183)
    org.springframework.security.web.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:342)
    org.springframework.security.web.authentication.logout.LogoutFilter.doFilter(LogoutFilter.java:105)
    org.springframework.security.web.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:342)
    org.springframework.security.web.context.SecurityContextPersistenceFilter.doFilter(SecurityContextPersistenceFilter.java:87)
    org.springframework.security.web.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:342)
    org.springframework.security.web.FilterChainProxy.doFilterInternal(FilterChainProxy.java:192)
    org.springframework.security.web.FilterChainProxy.doFilter(FilterChainProxy.java:160)
    org.springframework.web.filter.DelegatingFilterProxy.invokeDelegate(DelegatingFilterProxy.java:346)
    org.springframework.web.filter.DelegatingFilterProxy.doFilter(DelegatingFilterProxy.java:259)

请告知如何解决此异常。

4

1 回答 1

0

ISSUE 在数据库端，我UNIQUE INDEX在，customer_EmailAddress而且主键顺序必须等同于连接列

PRIMARY KEY (`Customer_EmailAddress`, `Address_Id`)
于 2012-10-29T14:20:38.463 回答