R中是否有Streamgraphs的实现？
流图是堆叠图的一种变体，是对 Havre 等人的 ThemeRiver 在基线选择、层排序和颜色选择方面的改进。
例子：
参考： http: //www.leebyron.com/else/streamgraph/
问问题
10802 次
5 回答
42
不久前我写了一个函数plot.stacked，也许可以帮助你。
功能是：
plot.stacked <- function(x,y, ylab="", xlab="", ncol=1, xlim=range(x, na.rm=T), ylim=c(0, 1.2*max(rowSums(y), na.rm=T)), border = NULL, col=rainbow(length(y[1,]))){
plot(x,y[,1], ylab=ylab, xlab=xlab, ylim=ylim, xaxs="i", yaxs="i", xlim=xlim, t="n")
bottom=0*y[,1]
for(i in 1:length(y[1,])){
top=rowSums(as.matrix(y[,1:i]))
polygon(c(x, rev(x)), c(top, rev(bottom)), border=border, col=col[i])
bottom=top
}
abline(h=seq(0,200000, 10000), lty=3, col="grey")
legend("topleft", rev(colnames(y)), ncol=ncol, inset = 0, fill=rev(col), bty="0", bg="white", cex=0.8, col=col)
box()
}
这是一个示例数据集和一个绘图：
set.seed(1)
m <- 500
n <- 15
x <- seq(m)
y <- matrix(0, nrow=m, ncol=n)
colnames(y) <- seq(n)
for(i in seq(ncol(y))){
mu <- runif(1, min=0.25*m, max=0.75*m)
SD <- runif(1, min=5, max=30)
TMP <- rnorm(1000, mean=mu, sd=SD)
HIST <- hist(TMP, breaks=c(0,x), plot=FALSE)
fit <- smooth.spline(HIST$counts ~ HIST$mids)
y[,i] <- fit$y
}
plot.stacked(x,y)
我可以想象你只需要调整多边形“底部”的定义来获得你想要的情节。
更新：
我再次尝试制作流图，并相信我或多或少地复制了函数中的想法plot.stream，可以在这个要点中找到，也可以在这篇文章的底部复制。在此链接中，我展示了其使用的更多详细信息，但这是一个基本示例：
library(devtools)
source_url('https://gist.github.com/menugget/7864454/raw/f698da873766347d837865eecfa726cdf52a6c40/plot.stream.4.R')
set.seed(1)
m <- 500
n <- 50
x <- seq(m)
y <- matrix(0, nrow=m, ncol=n)
colnames(y) <- seq(n)
for(i in seq(ncol(y))){
mu <- runif(1, min=0.25*m, max=0.75*m)
SD <- runif(1, min=5, max=30)
TMP <- rnorm(1000, mean=mu, sd=SD)
HIST <- hist(TMP, breaks=c(0,x), plot=FALSE)
fit <- smooth.spline(HIST$counts ~ HIST$mids)
y[,i] <- fit$y
}
y <- replace(y, y<0.01, 0)
#order by when 1st value occurs
ord <- order(apply(y, 2, function(r) min(which(r>0))))
y2 <- y[, ord]
COLS <- rainbow(ncol(y2))
png("stream.png", res=400, units="in", width=12, height=4)
par(mar=c(0,0,0,0), bty="n")
plot.stream(x,y2, axes=FALSE, xlim=c(100, 400), xaxs="i", center=TRUE, spar=0.2, frac.rand=0.1, col=COLS, border=1, lwd=0.1)
dev.off()
plot.stream() 的代码
#plot.stream makes a "stream plot" where each y series is plotted
#as stacked filled polygons on alternating sides of a baseline.
#
#Arguments include:
#'x' - a vector of values
#'y' - a matrix of data series (columns) corresponding to x
#'order.method' = c("as.is", "max", "first")
# "as.is" - plot in order of y column
# "max" - plot in order of when each y series reaches maximum value
# "first" - plot in order of when each y series first value > 0
#'center' - if TRUE, the stacked polygons will be centered so that the middle,
#i.e. baseline ("g0"), of the stream is approximately equal to zero.
#Centering is done before the addition of random wiggle to the baseline.
#'frac.rand' - fraction of the overall data "stream" range used to define the range of
#random wiggle (uniform distrubution) to be added to the baseline 'g0'
#'spar' - setting for smooth.spline function to make a smoothed version of baseline "g0"
#'col' - fill colors for polygons corresponding to y columns (will recycle)
#'border' - border colors for polygons corresponding to y columns (will recycle) (see ?polygon for details)
#'lwd' - border line width for polygons corresponding to y columns (will recycle)
#'...' - other plot arguments
plot.stream <- function(
x, y,
order.method = "as.is", frac.rand=0.1, spar=0.2,
center=TRUE,
ylab="", xlab="",
border = NULL, lwd=1,
col=rainbow(length(y[1,])),
ylim=NULL,
...
){
if(sum(y < 0) > 0) error("y cannot contain negative numbers")
if(is.null(border)) border <- par("fg")
border <- as.vector(matrix(border, nrow=ncol(y), ncol=1))
col <- as.vector(matrix(col, nrow=ncol(y), ncol=1))
lwd <- as.vector(matrix(lwd, nrow=ncol(y), ncol=1))
if(order.method == "max") {
ord <- order(apply(y, 2, which.max))
y <- y[, ord]
col <- col[ord]
border <- border[ord]
}
if(order.method == "first") {
ord <- order(apply(y, 2, function(x) min(which(r>0))))
y <- y[, ord]
col <- col[ord]
border <- border[ord]
}
bottom.old <- rep(0, length(x))
top.old <- rep(0, length(x))
polys <- vector(mode="list", ncol(y))
for(i in seq(polys)){
if(i %% 2 == 1){ #if odd
top.new <- top.old + y[,i]
polys[[i]] <- list(x=c(x, rev(x)), y=c(top.old, rev(top.new)))
top.old <- top.new
}
if(i %% 2 == 0){ #if even
bottom.new <- bottom.old - y[,i]
polys[[i]] <- list(x=c(x, rev(x)), y=c(bottom.old, rev(bottom.new)))
bottom.old <- bottom.new
}
}
ylim.tmp <- range(sapply(polys, function(x) range(x$y, na.rm=TRUE)), na.rm=TRUE)
outer.lims <- sapply(polys, function(r) rev(r$y[(length(r$y)/2+1):length(r$y)]))
mid <- apply(outer.lims, 1, function(r) mean(c(max(r, na.rm=TRUE), min(r, na.rm=TRUE)), na.rm=TRUE))
#center and wiggle
if(center) {
g0 <- -mid + runif(length(x), min=frac.rand*ylim.tmp[1], max=frac.rand*ylim.tmp[2])
} else {
g0 <- runif(length(x), min=frac.rand*ylim.tmp[1], max=frac.rand*ylim.tmp[2])
}
fit <- smooth.spline(g0 ~ x, spar=spar)
for(i in seq(polys)){
polys[[i]]$y <- polys[[i]]$y + c(fitted(fit), rev(fitted(fit)))
}
if(is.null(ylim)) ylim <- range(sapply(polys, function(x) range(x$y, na.rm=TRUE)), na.rm=TRUE)
plot(x,y[,1], ylab=ylab, xlab=xlab, ylim=ylim, t="n", ...)
for(i in seq(polys)){
polygon(polys[[i]], border=border[i], col=col[i], lwd=lwd[i])
}
}
于 2012-10-26T12:43:33.360 回答
10
这些天有一个流图htmlwidget：
https://hrbrmstr.github.io/streamgraph/
devtools::install_github("hrbrmstr/streamgraph")
library(streamgraph)
streamgraph(data, key, value, date, width = NULL, height = NULL,
offset = "silhouette", interpolate = "cardinal", interactive = TRUE,
scale = "date", top = 20, right = 40, bottom = 30, left = 50)
它产生非常漂亮的图表，甚至是交互式的。
编辑
另一种选择是使用ggTimeSeries，它使用 ggplot2 的语法：
# creating some data
library(ggTimeSeries)
library(ggplot2)
set.seed(10)
dfData = data.frame(
Time = 1:1000,
Signal = abs(
c(
cumsum(rnorm(1000, 0, 3)),
cumsum(rnorm(1000, 0, 4)),
cumsum(rnorm(1000, 0, 1)),
cumsum(rnorm(1000, 0, 2))
)
),
VariableLabel = c(rep('Class A', 1000),
rep('Class B', 1000),
rep('Class C', 1000),
rep('Class D', 1000))
)
# base plot
ggplot(dfData,
aes(x = Time,
y = Signal,
group = VariableLabel,
fill = VariableLabel)) +
stat_steamgraph() +
theme_bw()
于 2016-03-31T19:45:16.543 回答
9
在框中的漂亮代码中向 Marc 添加一行将使您更接近。（剩下的只是根据每条曲线的最大高度设置填充颜色。）
## reorder the columns so each curve first appears behind previous curves
## when it first becomes the tallest curve on the landscape
y <- y[, unique(apply(y, 1, which.max))]
## Use plot.stacked() from Marc's post
plot.stacked(x,y)
于 2012-10-26T15:54:48.847 回答
9
我使用lattice::xyplot. 代码在我的
spacetimeVis 存储库中。
下一个示例使用此数据集：
library(lattice)
library(zoo)
library(colorspace)
nCols <- ncol(unemployUSA)
pal <- rainbow_hcl(nCols, c=70, l=75, start=30, end=300)
myTheme <- custom.theme(fill=pal, lwd=0.2)
xyplot(unemployUSA, superpose=TRUE, auto.key=FALSE,
panel=panel.flow, prepanel=prepanel.flow,
origin='themeRiver', scales=list(y=list(draw=FALSE)),
par.settings=myTheme)
它产生这个图像。
xyplot需要两个功能才能工作：panel.flow和prepanel.flow：
panel.flow <- function(x, y, groups, origin, ...){
dat <- data.frame(x=x, y=y, groups=groups)
nVars <- nlevels(groups)
groupLevels <- levels(groups)
## From long to wide
yWide <- unstack(dat, y~groups)
## Where are the maxima of each variable located? We will use
## them to position labels.
idxMaxes <- apply(yWide, 2, which.max)
##Origin calculated following Havr.eHetzler.ea2002
if (origin=='themeRiver') origin= -1/2*rowSums(yWide)
else origin=0
yWide <- cbind(origin=origin, yWide)
## Cumulative sums to define the polygon
yCumSum <- t(apply(yWide, 1, cumsum))
Y <- as.data.frame(sapply(seq_len(nVars),
function(iCol)c(yCumSum[,iCol+1],
rev(yCumSum[,iCol]))))
names(Y) <- levels(groups)
## Back to long format, since xyplot works that way
y <- stack(Y)$values
## Similar but easier for x
xWide <- unstack(dat, x~groups)
x <- rep(c(xWide[,1], rev(xWide[,1])), nVars)
## Groups repeated twice (upper and lower limits of the polygon)
groups <- rep(groups, each=2)
## Graphical parameters
superpose.polygon <- trellis.par.get("superpose.polygon")
col = superpose.polygon$col
border = superpose.polygon$border
lwd = superpose.polygon$lwd
## Draw polygons
for (i in seq_len(nVars)){
xi <- x[groups==groupLevels[i]]
yi <- y[groups==groupLevels[i]]
panel.polygon(xi, yi, border=border,
lwd=lwd, col=col[i])
}
## Print labels
for (i in seq_len(nVars)){
xi <- x[groups==groupLevels[i]]
yi <- y[groups==groupLevels[i]]
N <- length(xi)/2
## Height available for the label
h <- unit(yi[idxMaxes[i]], 'native') -
unit(yi[idxMaxes[i] + 2*(N-idxMaxes[i]) +1], 'native')
##...converted to "char" units
hChar <- convertHeight(h, 'char', TRUE)
## If there is enough space and we are not at the first or
## last variable, then the label is printed inside the polygon.
if((hChar >= 1) && !(i %in% c(1, nVars))){
grid.text(groupLevels[i],
xi[idxMaxes[i]],
(yi[idxMaxes[i]] +
yi[idxMaxes[i] + 2*(N-idxMaxes[i]) +1])/2,
gp = gpar(col='white', alpha=0.7, cex=0.7),
default.units='native')
} else {
## Elsewhere, the label is printed outside
grid.text(groupLevels[i],
xi[N],
(yi[N] + yi[N+1])/2,
gp=gpar(col=col[i], cex=0.7),
just='left', default.units='native')
}
}
}
prepanel.flow <- function(x, y, groups, origin,...){
dat <- data.frame(x=x, y=y, groups=groups)
nVars <- nlevels(groups)
groupLevels <- levels(groups)
yWide <- unstack(dat, y~groups)
if (origin=='themeRiver') origin= -1/2*rowSums(yWide)
else origin=0
yWide <- cbind(origin=origin, yWide)
yCumSum <- t(apply(yWide, 1, cumsum))
list(xlim=range(x),
ylim=c(min(yCumSum[,1]), max(yCumSum[,nVars+1])),
dx=diff(x),
dy=diff(c(yCumSum[,-1])))
}
于 2013-12-10T14:45:47.417 回答
5
也许是这样的ggplot2。我稍后将对其进行编辑，并将 csv 数据上传到合理的地方。
我需要考虑的几个问题：
- 从平滑图表中获取 y 值，以便您可以为高票房电影的名称重叠绘制
- 根据您的示例在 x 轴上添加“波浪”。
稍微考虑一下，两者都应该没问题。可悲的是，交互性会很棘手。也许会看看googleVis。
## PRE-REQS
require(plyr)
require(ggplot2)
## GET SOME BASIC DATA
films<-read.csv("box.csv")
## ALL OF THIS IS FAKING DATA
get_dist<-function(n,g){
dist<-g-(abs(sort(g-abs(rnorm(n,g,g*runif(1))))))
dist<-c(0,dist-min(dist),0)
dist<-dist*g/sum(dist)
return(dist)
}
get_dates<-function(w){
start<-as.Date("01-01-00",format="%d-%m-%y")+ceiling(runif(1)*365)
return(start+w)
}
films$WEEKS<-ceiling(runif(1)*10)+6
f<-ddply(films,.(RANK),function(df)expand.grid(RANK=df$RANK,WEEKGROSS=get_dist(df$WEEKS,df$GROSS)))
weekly<-merge(films,f,by=("RANK"))
## GENERATE THE PLOT DATA
plot.data<-ddply(weekly,.(RANK),summarise,NAME=NAME,WEEKDATE=get_dates(seq_along(WEEKS)*7),WEEKGROSS=ifelse(RANK %% 2 == 0,-WEEKGROSS,WEEKGROSS),GROSS=GROSS)
g<-ggplot() +
geom_area(data=plot.data[plot.data$WEEKGROSS>=0,],
aes(x=WEEKDATE,
ymin=0,
y=WEEKGROSS,
group=NAME,
fill=cut(GROSS,c(seq(0,1000,100),Inf)))
,alpha=0.5,
stat="smooth", fullrange=T,n=1000,
colour="white",
size=0.25,alpha=0.5) +
geom_area(data=plot.data[plot.data$WEEKGROSS<0,],
aes(x=WEEKDATE,
ymin=0,
y=WEEKGROSS,
group=NAME,
fill=cut(GROSS,c(seq(0,1000,100),Inf)))
,alpha=0.5,
stat="smooth", fullrange=T,n=1000,
colour="white",
size=0.25,alpha=0.5) +
theme_bw() +
scale_fill_brewer(palette="RdPu",name="Gross\nEUR (M)") +
ylab("") + xlab("")
b<-ggplot_build(g)$data[[1]]
b.ymax<-max(b$y)
## MAKE LABELS FOR GROSS > 450M
labels<-ddply(plot.data[plot.data$GROSS>450,],.(RANK,NAME),summarise,x=median(WEEKDATE),y=ifelse(sum(WEEKGROSS)>0,b.ymax,-b.ymax),GROSS=max(GROSS))
labels<-ddply(labels,.(y>0),transform,NAME=paste(NAME,GROSS),y=(y*1.1)+((seq_along(y)*20*(y/abs(y)))))
## PLOT
g +
geom_segment(data=labels,aes(x=x,xend=x,y=0,yend=y,label=NAME),size=0.5,linetype=2,color="purple",alpha=0.5) +
geom_text(data=labels,aes(x,y,label=NAME),size=3)
dput()如果有人想玩的话，这里有一部 df 电影：
structure(list(RANK = 1:50, NAME = structure(c(2L, 45L, 18L,
33L, 32L, 29L, 34L, 23L, 4L, 21L, 38L, 46L, 15L, 36L, 26L, 49L,
16L, 8L, 5L, 31L, 17L, 27L, 41L, 3L, 48L, 40L, 28L, 1L, 6L, 24L,
47L, 13L, 10L, 12L, 39L, 14L, 30L, 20L, 22L, 11L, 19L, 25L, 35L,
9L, 43L, 44L, 37L, 7L, 42L, 50L), .Label = c("Alice in Wonderland",
"Avatar", "Despicable Me 2", "E.T.", "Finding Nemo", "Forrest Gump",
"Harry Potter and the Deathly Hallows Part 1", "Harry Potter and the Deathly Hallows Part 2",
"Harry Potter and the Half-Blood Prince", "Harry Potter and the Sorcerer's Stone",
"Independence Day", "Indiana Jones and the Kingdom of the Crystal Skull",
"Iron Man", "Iron Man 2", "Iron Man 3", "Jurassic Park", "LOTR: The Return of the King",
"Marvel's The Avengers", "Pirates of the Caribbean", "Pirates of the Caribbean: At World's End",
"Pirates of the Caribbean: Dead Man's Chest", "Return of the Jedi",
"Shrek 2", "Shrek the Third", "Skyfall", "Spider-Man", "Spider-Man 2",
"Spider-Man 3", "Star Wars", "Star Wars: Episode II -- Attack of the Clones",
"Star Wars: Episode III", "Star Wars: The Phantom Menace", "The Dark Knight",
"The Dark Knight Rises", "The Hobbit: An Unexpected Journey",
"The Hunger Games", "The Hunger Games: Catching Fire", "The Lion King",
"The Lord of the Rings: The Fellowship of the Ring", "The Lord of the Rings: The Two Towers",
"The Passion of the Christ", "The Sixth Sense", "The Twilight Saga: Eclipse",
"The Twilight Saga: New Moon", "Titanic", "Toy Story 3", "Transformers",
"Transformers: Dark of the Moon", "Transformers: Revenge of the Fallen",
"Up"), class = "factor"), YEAR = c(2009L, 1997L, 2012L, 2008L,
1999L, 1977L, 2012L, 2004L, 1982L, 2006L, 1994L, 2010L, 2013L,
2012L, 2002L, 2009L, 1993L, 2011L, 2003L, 2005L, 2003L, 2004L,
2004L, 2013L, 2011L, 2002L, 2007L, 2010L, 1994L, 2007L, 2007L,
2008L, 2001L, 2008L, 2001L, 2010L, 2002L, 2007L, 1983L, 1996L,
2003L, 2012L, 2012L, 2009L, 2010L, 2009L, 2013L, 2010L, 1999L,
2009L), GROSS = c(760.5, 658.6, 623.4, 533.3, 474.5, 460.9, 448.1,
436.5, 434.9, 423.3, 422.7, 415, 409, 408, 403.7, 402.1, 395.8,
381, 380.8, 380.2, 377, 373.4, 370.3, 366.9, 352.4, 340.5, 336.5,
334.2, 329.7, 321, 319.1, 318.3, 317.6, 317, 313.8, 312.1, 310.7,
309.4, 309.1, 306.1, 305.4, 304.4, 303, 301.9, 300.5, 296.6,
296.3, 295, 293.5, 293), WEEKS = c(9, 9, 9, 9, 9, 9, 9, 9, 9,
9, 9, 9, 9, 9, 9, 9, 9, 9, 9, 9, 9, 9, 9, 9, 9, 9, 9, 9, 9, 9,
9, 9, 9, 9, 9, 9, 9, 9, 9, 9, 9, 9, 9, 9, 9, 9, 9, 9, 9, 9)), .Names = c("RANK",
"NAME", "YEAR", "GROSS", "WEEKS"), row.names = c(NA, -50L), class = "data.frame")
于 2013-12-13T12:50:16.823 回答