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每次我尝试运行这个 xhtml 文件时，它只显示 javascript 文件，它不运行该函数。我究竟做错了什么？为什么函数不运行？我对 JS 和 xhtml 相当陌生，因此欢迎和感谢任何和所有帮助。这是我的代码

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<!--Submit form, Assignment 2-->
<html xmlns = "http://www.w3.org/1999/xhtml">
<head>

<script type = "text/javaScript" src = "mss58.js"></script>
<title> Submit Form Assignment </title>
<meta charset="UTF-8">

</head>


<body>

<h1>Please Fill out the following Form</h1>
<form name ="SubmitForm" action = "mss58.js" onsubmit = "validate()" method="run">
Name: <input type ="text" name="firstname"><br />
Email address: <input type = "text" name="emailaddress"><br />
Password: <input type = "password" name = "pwd"><br />
Confirm Password: <input type = "password" name = "cpwd"><br />
Gender: <input type = "radio" name = "gender" value = "male">Male
        <input type = "radio" name = "gender" value = "female">Female<br />
        <br />
Comments: <br />
          <textarea rows ="10" cols = "50"></textarea><br />
<input type = "submit" value = "Submit">
</form>           

</body>
</html>

编辑：我得到了正确提交的表单，但是我的 javascript 文件不想检查。我猜我的 if 语句不起作用。当我输入无效的密码、用户名或电子邮件时没有弹出警报时，有人可以试一试并告诉我为什么吗？我确定这很明显，我只是在这门课之前从未使用过 javascript

function validate(){

var name = document.forms["SubmitForm"]["firstname"].value;
var email = document.forms["SubmitForm"]["emailaddress"].value;
var password = document.forms["SubmitForm"]["pwd"].value;
var cpass = document.forms["SubmitForm"]["cpwd"].value;

var arrloc = email.indexOf("@");
var perloc = email.lastIndexOf(".");

var alph = false;
var num = false;
var sym = false;


if(name == null || name == ""){
    alert("You must fill out the Name field");
    return false;
}


if(arrloc < 1 || perloc < arrloc + 2 || perloc + 2 >= email.length){
    alert("Email is not valid");
    return false;
}


for(var i = 0, i < password.length-1, i++){
    if(password.substring(i,i+1) == /[a-z]/){
        alph = true;
    }
    if(password.substring(i,i+1) == /[A-Z]/){
        alph = true;
    }
    if(password.substring(i,i+1) == /[0-9]/){
        num = true;
    }
    if(password.substring(i,i+1) == /[^\w+$]/){
        sym = true;
    }
}


if(alph == true && num == true && sym == true){
    return true;
}else{
    alert("Your password is invalid!");
    return false;
}


if(password == cpass){
    return true;
}else{
    alert("Your passwords do not match!");
    return false;
}


};

validate();
4

2 回答 2

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你需要改变

<form name ="SubmitForm" action = "mss58.js" onsubmit = "validate()" method="run">

至

<form name ="SubmitForm" action = "TARGET_PAGE.php" onsubmit = "return validate()" method="POST">

在您的 JavaScript 验证函数中，它应该在数据不正确时返回 false，否则返回 true。

于 2012-10-26T05:42:18.620 回答
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您应该将您的 javascript 代码包含到<script>标记中。

为了运行定义的函数，你必须调用它，例如，像这样：validate()

于 2012-10-26T05:32:33.787 回答