对格式化灾难感到抱歉，我是 stackoverflow 和 Java 的新手。我在应该包含两个名称列表和相应目录#s 的代码中有两个问题。在代码中，我应该能够搜索、显示、编辑和退出。显示和退出已经工作，但我在搜索和编辑时遇到问题。我已经强调了问题所在的信息。我将不胜感激任何帮助。
public static void Search(String[] arr, String find) {
for (int i = 0; i < 10; i++) {
//首要问题！！这是我稍后调用的在字符串数组中搜索代码位的方法。我需要能够在数组中搜索某些字符（数组是名称，所以“mith”会调出“smith”。稍后在代码中我在开关内部调用它。我想我需要类似“ arr[i].equals(find)" 但我不知道语法
}
}
public static void main(String[] args) {
Scanner inp = new Scanner(System.in);
String userInput1 = "";
String userInput2 = "";
String userInput3 = "";
// Ask User to chose between faculty and students
System.out.println("Are you searching for Students or Faculty? ");
userInput1 = inp.nextLine().toLowerCase();
if (userInput1.startsWith("f")) {
//Block 1 for faculty
do {
String[] Faculty = {"0. Jack Kerouac", "1. Les Claypool", "2. Tom Waits", "3. Kurt Vonnegut",
"4. Hunter Thompson", "5. Princess Bubblegum", "6. John Smith", "7. Jack Thompson", "8. Jeff Dahmer", "9. Martin King"};
System.out.println("What would you like to do?");
System.out.println("S: Search");
System.out.println("E: Edit");
System.out.println("D: Display");
System.out.println("Q: Quit");
// user input
userInput2 = inp.nextLine().toLowerCase();
System.out.println("");
// Respond based on user input
switch (userInput2.charAt(0)) {
case 's':
System.out.println("Type part of the persons name: ");
String x = inp.nextLine().toLowerCase();
String[] y = Faculty;
Search(y, x);
break;
case 'e':
//这是我的编辑数组问题。我尝试了几种不同的方法来使其工作，但是在重新分配 Faculty[q] 时，每一种方法都遇到了问题。当您运行程序时，它会从“输入新目录信息”跳回主循环。如何更改数组中的字符串？
System.out.println("Enter the catalog number of the entry trying to edit: ");
int q = inp.nextInt();
System.out.println(Faculty[q]);
System.out.println("Enter new catalog information: ");
String NewFac = inp.nextLine();
Faculty[q] = String NewFac;
System.out.println(Faculty[q]);
break;
case 'd':
System.out.println("Enter a catalog number between 0-9: ");
int o = inp.nextInt();
System.out.println(Faculty[o]);
break;
}
// Blank line, for formatting
System.out.println("");
} while (!userInput2.equals("q"));
System.out.println("Done.");
} else {
//block 2 for students
do {
String[] Student = {"0. Alice Johnson", "1. Johnny Marr", "2. Johnny Johnson", "3. Robert Smith",
"4. Ian Curtis", "5. Luke Shapiro", "6. David Newman", "7. Ren Newman", "8. Camille Kaslan", "9. Alexander Shulgin"};
System.out.println("What would you like to do?");
System.out.println("S: Search");
System.out.println("E: Edit");
System.out.println("D: Display");
System.out.println("Q: Quit");
// user input
userInput3 = inp.nextLine().toLowerCase();
System.out.println("");
// Respond based on user input
switch (userInput3.charAt(0)) {
case 's':
System.out.println("Type part of the persons name: ");
String x = inp.nextLine().toLowerCase();
String[] y = Student;
Search(y, x);
break;
case 'e':
System.out.println("Enter the catalog number of the entry trying to edit: ");
int r = inp.nextInt();
System.out.println(Student[r]);
System.out.println("Enter new catalog information: ");
Student[r] = inp.nextLine();
System.out.println(Student[r]);
break;
case 'd':
System.out.println("Enter a catalog number between 0-9: ");
int n = inp.nextInt();
System.out.println(Student[n]);
break;
}
// Blank line, for formatting
System.out.println("");
} while (!userInput3.equals("q"));
System.out.println("Done.");
}
如果不清楚，第一个问题是在我的搜索方法中的 for 循环中放入什么，称为“搜索”。第二个问题是如何从用户那里获取新信息并将其替换为名称数组（编辑功能）。