好的,我知道它已经有一段时间了,我不确定我是否应该开始一个新线程
但我已经想出了如何删除以删除两个中间部分,所有括号和 srgba,以及零 alpha 的行,但不知何故它在文本文件中留下了一个开放空间。如果有任何人都可以看到的任何改进。
$fh = fopen("pcmanD.txt", "r");
$fg = fopen("pcmanJ.txt", "wt");
$new_array = ""; $parts = "";
while (!feof($fh)) {
$line = fgets($fh);
$lines[] = $line;
$newword = "";
$match1 ="/:\s?\s?\(\s?\s?\d+,\s?\s?\d+,\s?\s?\d+,\s?\s?\d+\)\s?\s?#[a-zA-Z0-9]{6,8}\s?\s?srgba/";
$match2 ="/^\s\s?/";
$match3 = "/\s\(/";
$match4 = "/\)/";
$match5 = "/[0-9]{1,3},[0-9]{1,3},[0-9]{1,3},[0-9]{1,3},[0-9]{1,3},0[^\.]/";
$parts1 = preg_replace($match1,"", $line );
$parts2 = preg_replace($match2,"", $parts1 );
$parts3 = preg_replace($match3,",", $parts2 );
$parts4 = preg_replace($match4,"", $parts3 );
$parts5 = preg_replace($match5,"",$parts4);
echo "<pre>";
print_r($parts5);
echo "</pre>";
fwrite($fg, $parts5);
}
fclose($fg);
fclose($fh);
但是这段代码出现了新问题,我在比赛后的浮点数上得到了两倍或三倍。
$thisisit[] = "";
$thisisit2[] = "";
$countThis = 0;
$fh = fopen("sometext.txt", "r");
$new_array = ""; $parts = "";
while (!feof($fh)) {
$line = fgets($fh);
$line2 = $line;
$newword = "";
$match1 ="/^\s*?[\d]+,[\d]+/";
$parts1 = preg_match($match1, $line, $regs);
foreach($regs as $key => $lame) {
$thisisit[] = $lame;
}
$match2 ="/(?:(\d{1,3},\d{1,3},))(\d{1,3},\d{1,3},\d{1,3},[01][\.]?[\d]*)/";
$parts2 = preg_match($match2, $line2, $regs2);
foreach($regs2 as $key2 => $lame2) {
$thisisit2[] =$lame2;
}
$countLame = count($thisisit);
}
echo "</script>";
$newCounter = 0;
for($i = 0; $i < (500); $i++) {
echo $thisisit[$i] . "<br />";
echo $thisisit2[$newCounter] . "<br />" ;
$newCounter = $newCounter +4;
}
fclose($fh);
这是我正在处理的文本文件中的一些文本
42,23,162,166,48,0.156863
43,23,162,166,47,0.156863
44,23,167,170,67,0.219608
45,23,162,166,47,0.156863
46,23,167,170,67,0.219608
47,23,162,166,37,0.117647
48,23,162,167,32,0.0941176
86,23,163,167,40,0.12549
87,23,160,164,47,0.164706
88,23,188,190,122,0.352941
86,24,233,234,197,0.486275
87,24,251,250,250,1
88,24,251,250,250,1
89,24,251,250,250,1