我有一个需要大约 10 秒才能运行的数据收集例程,然后将数据保存到 CSV 文件中:
string file = Path.Combine(Environment.GetFolderPath(Environment.SpecialFolder.MyDocuments), "Book1.csv");
StreamWriter streamWriter1 = new StreamWriter(File.Open(file, FileMode.Create, FileAccess.Write));
DataTable table = GetMyData(); // takes about 10 seconds
foreach (DataRow row in table.Rows) {
object[] item = row.ItemArray;
for (int i = 0; i < item.Length; i++) {
streamWriter1.Write(item.ToString() + ",");
}
streamWriter1.WriteLine();
}
streamWriter1.Close();
Process.Start("Excel", "book1.csv");
Excel 也需要一些时间才能启动(5 到 10)。
我想修改这种技术,以便在我的数据收集之前调用 Excel,这样应用程序将在我收集数据时运行,然后让它显示带有数据的文件。
考虑到这一点,这就是我将代码修改为的内容,但它总是告诉我文件不存在(即使它存在):
Process excel = Process.Start("Excel");
if (excel != null) {
string file = Path.Combine(Environment.GetFolderPath(Environment.SpecialFolder.MyDocuments), "Book1.csv");
StreamWriter streamWriter1 = new StreamWriter(File.Open(file, FileMode.Create, FileAccess.Write));
DataTable table = GetMyData(); // takes about 10 seconds
foreach (DataRow row in table.Rows) {
object[] item = row.ItemArray;
for (int i = 0; i < item.Length; i++) {
streamWriter1.Write(item.ToString() + ",");
}
streamWriter1.WriteLine();
}
streamWriter1.Close();
for (int i = 0; i < 100; i++) { // simulate the data collection routine
Thread.Sleep(100);
}
excel.StartInfo.Arguments = file;
excel.StartInfo.ErrorDialog = true;
excel.StartInfo.UseShellExecute = false;
excel.StartInfo.WorkingDirectory = Environment.GetFolderPath(Environment.SpecialFolder.MyDocuments);
try {
excel.Start();
} catch (Exception err) {
Console.WriteLine(err.Message); // <= Message is "The system cannot find the file specified"
}
}
有什么想法吗?我如何正确地将文件发送到活动进程?