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我对用户菜单有一个问题。因此,我希望经过身份验证的用户可以在菜单中看到他/她的个人资料页面和注销(链接)。它在索引页面上工作(当我登录时):index, page1, profile, logout,但是,如果我转到 page1 ,我可以在菜单中看到:index, page1, login,而不是 profile 和 logout 。如何解决?

在网址中:

url(r'^accounts/login/$', 'django.contrib.auth.views.login' ),
url(r'^accounts/logout/$', 'django.contrib.auth.views.logout_then_login' ),
url(r'^accounts/profile/$', 'my_app.views.profile' ),

在意见中:

def profile(request):
    if  not request.user.is_authenticated():
        return HttpResponseRedirect("/accounts/login/")        
    else:
        user = request.user.is_authenticated()
        return  render_to_response('profile.html',locals()) 

index.html 的一部分:

{% if user.is_authenticated or request.user.is_authenticated %}
    <li><a href="/accounts/profile/">Profile</a></li>
    <li><a href="/accounts/logout/">logout</a></li>
{% else %}
    <li><a href="/accounts/login/">login</a></li>
{% endif %}

登录.html:

{% extends "index.html" %}
{% load url from future %}

{% block application %}

{% if form.errors %}
<p>Try one more time</p>
{% endif %}

<form method="post" action="{% url 'django.contrib.auth.views.login' %}">
{% csrf_token %}
<table>
<tr>
    <td>{{ form.username.label_tag }}</td>
    <td>{{ form.username }}</td>
</tr>
<tr>
    <td>{{ form.password.label_tag }}</td>
    <td>{{ form.password }}</td>
</tr>
</table>

<input type="submit" value="Login" />
<input type="hidden" name="next" value="{{ next }}" />
</form>

{% endblock %}

profile.html:

{% extends "index.html" %}
{% block application %}
{% if request.user.is_authenticated %}
    <p>Welcome, {{ request.user.username }}. Thanks for logging in.</p>
{% else %}
    <p>Welcome, new user. Please log in.</p>
{% endif %}
{% endblock %}

page1.html:

{% extends "index.html" %}
{% block application %}
some for loops here
{% endblock %}

第 1 页的浏览量:

def car(request):
    all_cars = Car.objects.all().filter(active=1).values('id', 'name')
    return render_to_response('page1.html', {'all_cars': all_cars})
4

2 回答 2

0

总是添加context_instance

render_to_response('profile.html',locals(), context_instance=RequestContext(request))
于 2012-10-25T10:57:48.090 回答
0

user渲染模板时不必手动传递。尝试这样做。

view.py 中

from django.contrib.auth.decorators import login_required
from django.shortcuts import render

@login_required
def profile(request):
    return render(request, 'profile.html')

settings.py

LOGIN_URL = '/accounts/login/'

index.html中:

{% if user.is_authenticated %}
    <li><a href="/accounts/profile/">Profile</a></li>
    <li><a href="/accounts/logout/">logout</a></li>
{% else %}
    <li><a href="/accounts/login/">login</a></li>
{% endif %}

profile.html中

{% extends "index.html" %}
{% block application %}
{% if user.is_authenticated %}
    <p>Welcome, {{ user.username }}. Thanks for logging in.</p>
{% else %}
    <p>Welcome, new user. Please log in.</p>
{% endif %}
{% endblock %}

在 page1 视图中:

from django.shortcuts import render
from django.contrib.auth.decorators import login_required
# If you want only authenticated users to access this page
@login_required
def car(request):
    all_cars = Car.objects.all().filter(active=1).values('id', 'name')
    return render(request, 'page1.html', {'all_cars': all_cars})

PS:我强烈建议您使用命名网址并使用网址名称而不是硬编码网址。

于 2012-10-25T11:33:15.690 回答